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3 years ago

Which kingdom(s) include organisms that are autotrophic and heterotrophic?

Chemistry

2 answers:

Gnom [1K]3 years ago

6 0

Answer:

Explanation:

Plantae Animalia Archaebacteria and Animalia Protista and Eubacteria . Protista and Eubacteria kingdom(s) include organisms that are autotrophic or heterotrophic

Ksivusya [100]3 years ago

6 0

Explanation:

The kingdom where the autotrophic and heterotrophic belong is known to be the bacteria, archaea, eukarya, protista kingdom. There is also kingdom where in they are only autotrophic and this is Plantae kingdom. Also, there are also kingdom wherein they are only heterotrophic and these are fungi and animalia kingdom.

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How many grams of copper Cu, 63.54 g/mol are in 3.42 moles copper

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Answer:
Mass = 217.30 g

Solution:

Mass and moles are related to each other as,

Moles = Mass / M.mass ---- (1)

Where;
Moles = 3.42

M.Mass = 63.54 g.mol⁻¹

Solving eq. 1 for Mass,

Mass = Moles × M.mass
Putting Values,
Mass = 3.42 mol × 63.54 g.mol⁻¹

Mass = 217.30 g

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Two samples of potassium iodide are decomposed into their constituent elements. The first sample produced 13.0 g of potassium an

Cerrena [4.2K]

Answer:

79.4 kg

Explanation:

The formula for potassium iodide is:-

$KI$

This means that they are present in the same mole ration, i.e. 1 : 1

Also for 2 samples, the ratio of the masses must be equal .

So,

$\frac{Mass\ of\ potassium\ in\ sample\ 1}{Mass\ of\ Iodine\ in\ sample\ 1}=\frac{Mass\ of\ potassium\ in\ sample\ 2}{Mass\ of\ Iodine\ in\ sample\ 2}$

Thus,

Mass of potassium in sample 1 = 13.0 g

Mass of Iodine in sample 1 = 42.3 g

Mass of potassium in sample 2 = 24.4 kg

Applying in the above formula, we get that:-

$\frac{13.0\ g}{42.3\ g}=\frac{24.4\ kg}{Mass\ of\ Iodine\ in\ sample\ 2}$

Mass of iodine in sample 2 = 79.4 kg

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3 years ago

Melting water is an example of a physical change because (3 points)

ladessa [460]

The water changes state.

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According to Charles's law, what will happen to the volume of these balloons as temperature

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Answer:

The volume will decrease and the balloons will be smaller

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