Answer:
C = 0.3 F
Explanation:
The expression for a voltage in a capacitor with an initial voltage V₀, as a function of time, is given by the following equation:
![V= Vo*e^{-t/RC}](https://tex.z-dn.net/?f=V%3D%20Vo%2Ae%5E%7B-t%2FRC%7D)
When V = =.37*V₀, we have the following expression:
![\frac{V}{Vo} = e^{-t/RC} = 0.37](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BVo%7D%20%3D%20e%5E%7B-t%2FRC%7D%20%3D%200.37)
Applying ln to both sides, we have:
![\frac{-t}{RC} = ln 0.37 = -1](https://tex.z-dn.net/?f=%5Cfrac%7B-t%7D%7BRC%7D%20%3D%20ln%200.37%20%3D%20-1)
⇒ t = R*C
if t= 300 s, and R = 10³ Ω, we can solve for C as follows:
![C = \frac{t}{R} = \frac{3e2 s}{1e3 ohms} = 0.3 F](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7Bt%7D%7BR%7D%20%3D%20%5Cfrac%7B3e2%20s%7D%7B1e3%20ohms%7D%20%3D%200.3%20F)
So, the required value for C is 0.3 F.
Answer:
See attachment for step by step approach to get answers.
Explanation:
Given that;
The stream function for a certain incompressible flow field is given by the expression ψ = −Ur sinθ+qθ=2π. Obtain an expres- sion for the velocity field. Find the stagnation point(s) where jV ! j=0, and show that ψ =0 there.
See attachment.