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nignag [31]
3 years ago
15

Water flows through a pipe and enters a section where the cross sectional area is larger. Viscosity, friction, and gravitational

effects are negligible. Choose the letter of the correct statement about the change in pressure p and average velocity V.
(A) P2 is less than P1 and V2 is less than V1
(B) P2 is less than P1 and V2 is greater than V1
(C) P2 is greater than P1 and V2 is less than V1
(D) P2 is greater than P1 and V2 is greater than V1
Engineering
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

(A) and (D)

Explanation:

1) P2 is less than P1, that is when P1 increases in pressure, the velocity V1 of the water also increases. Therefore, on the other hand, since P2 is directly proportional to V1, P2 and V2 will be less than P1 and V1 respectively.

2) For P2 greater than P1 and V2 also is greater than V1. Since P2 is directly proportional to V2, hence, when P2 increases in pressure, P1 reduces in pressure. Similarly, velocity, V2 also increases and V1 reduces.

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A power cycle under development has two options for a condenser. One outputs saturated water and one outputs saturated vapor. Th
agasfer [191]

Answer:

408 J/kg

662696.7 J/kg

Explanation:

Workdone by compression process in a pump can be isothermally expressed as :

W = P_1V_1 \ In \frac{P_2}{P_1}

For water at inlet pressure 1. 0 bar;

the specific values for :

saturated vapor v_g = 1.694 m^2 kg

saturated liquid v_f = 0.001043 \  m^2 kg

∴ we have

P_1 = 1.0 bar = 1. 0 × 10⁵ N/m²

P_2 = 50 bar = 50  × 10⁵ N/m²

For saturated water output from condenser work; we have

W = P_1V_f \ In (\frac{P_2}{P_1})

W = (1.0*10^{-5})(0.001043) In ( \frac{50}{10} ) J/kg

W = 408 J/kg

For saturated vapor output from condenser

Work required :

W = P_1V_g \ In ( \frac{P_2}{P_1} )

W = 1.0*10^5*1.694 \ In ( \frac{50}{1.0}) J/kg

W = 662696.7 J/kg

5 0
3 years ago
Read 2 more answers
3. How can statistical analysis of a dataset inform a design process?
MrRa [10]

Explanation:

I don't know I'm so sorry

6 0
3 years ago
When preparing a foundation for a heavy duty machine tool, discuss any four (4) statics machine characteristics to be considered
kozerog [31]

Answer:

1 ) Accuracy of the Machine Tool

2) Load bearing capacity

3) Linearity in the product line

4) Torque of the machine

Explanation:

we know that machine tool is the permanent essential in manufacturing industries

it is a machine use for different form like cutting , grinding and boring etc

so 1st is

1 ) Accuracy of the Machine Tool

we know it is very important Characteristic of the machine tool because when we use it in manufacturing unit Accuracy of the Machine Tool should be higher concern

2) Load bearing capacity

we should very careful about Load bearing capacity because how much amount of load tool will bear check by some parameter like creep , shear stress and strength etc

3) Linearity in the product line

Linearity in the product line mean that it should be group of related product produced by the any one of the manufacturer otherwise it will take time or it may be intermixing

4) Torque of the machine

we know that Torque is a rotational force or a turning force so amount of force multiplied by the distance of the operation

and we know torque per second give the power rating of machine tool

5 0
4 years ago
Inspections may be_____ or limited to a specific area such as electrical or plumbing
Nuetrik [128]
A is the answer for the sentence
4 0
3 years ago
An automotive fuel has a molar composition of 85% ethanol (C2H5OH) and 15% octane (C8H18). For complete combustion in air, deter
slava [35]

Answer:

a) 1

b) 1813.96 MJ/kmol

c) 32.43 MJ/kg ,  1980.39 MJ/Kmol

Explanation:

molar mass of  ethanol (C2H5OH) = 46 g/mol

molar mass of   octane (C8H18) = 114 g/mol

therefore the moles of ethanol and octane

ethanol =  0.85 / 46

octane = 0.15 / 114

a) determine the molar air-fuel ratio and air-fuel ratio by mass

attached below

mass of air / mass of fuel = 12.17 / 1 = 12.17

b ) Determine the lower heating value

LHV  of  ( C2H5OH) = 26.8 * 46 = 1232.8 MJ/kmol

LHV  of (C8H18). = 44.8 mj/kg * 114 kg/kmol = 5107.2 MJ/Kmol

LHV ( MJ/kmol)  for fuel mixture = 0.85 * 1232.8 + 0.15 * 5107.2 = 1813.96 MJ/kmol

c) Determine higher heating value  ( HHV )

HHV of (C2H5OH) = 29.7 * 46 = 1366.2 MJ/kmol

HHV of C8H18 = 47.9 MJ/kg * 114 = 5460.6 MJ/kmol

HHV  in MJ/kg  = 0.85 * 29.7 + 0.15 * 47.9  = 32.43 MJ/kg

HHV in  MJ /kmol  =  0.85 * 1366.2 + 0.15 * 5460.8 = 1980.39 MJ/Kmol

4 0
3 years ago
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