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3 years ago

11

Which of the following caught in or caught between hazard poses the greatest risk when working in excavations and trenches? A. B

eing pinned B. Cave-ins C. Equipment falling into trenches D. Severing of underground utilities

2 answers:

RSB [31]3 years ago

6 0

I believe the correct answer is b.) cave-ins

Vlada [557]3 years ago

4 0

A being pinned if a big bolder falls on you

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A ____________ is a condition or behavior that may threaten an individual's well-being

pickupchik [31]

It would be risk factor

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2 years ago

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You own a high speed digital camera that can take a picture every 0.5 seconds. You decide to take a picture every 0.5 seconds of

Vesnalui [34]

-- There is no need to develop the pictures. They are available immediately in a digital camera.

-- There is no change in the teacher from one picture to the next.

-- The distance the watermelon falls from the teacher in each new picture is more in each picture than in the picture before it. (C)

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2 years ago

The second-order decomposition of hi has a rate constant of 1.80 x 10−3 m−1 s−1. How much hi remains after 45.6 s if the initial

zlopas [31]

Answer:

2.9 M

Explanation:

The concentration-time equation for a second order reaction is:

1/[A] = kt + 1/[A°]

Where,

A = concentration remaining at time, t

A° = initial concentration

k = rate constant

1/[A] = (1.80 x 10^-3) * (45.6) + 1/3.81

1/[A] = 0.345

= 1/0.345

= 2.9 M.

6 0

3 years ago

I need help on this!

sergij07 [2.7K]

Try looking it up. that might help

8 0

2 years ago

A 4-m long wire with a mass of 40 g is under tension. A transverse wave for which the frequency is 860 Hz, the wavelength is 0.5

inn [45]

Answer:

Maximum acceleration will be $195372m/sec^2$

Explanation:

It is given mass m =40 gram = 0.04 kg

Length of the wire l = 4 m

Frequency of transverse wave f = 860 Hz

Wavelength $\lambda =0.5m$

Amplitude of the propagating wave $A=6.7mm=0.0067m$

Angular frequency is equal to $\omega =2\pi f=2\times 3.14\times 860=5400rad/sec$

Maximum acceleration is equal to $a=\omega ^2A=5400^2\times 0.0067=195372m/sec^2$

So maximum acceleration will be $195372m/sec^2$

4 0

3 years ago