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pshichka [43]
3 years ago
7

Help me please :) asap

Chemistry
1 answer:
Dahasolnce [82]3 years ago
7 0

<em>Answer :</em> C - 1.02 x 10²³


<em>Explanation ;</em>


1 molecule of Al(NO₃)₃ has 3 N atoms.


Al(NO₃)₃ → Al + 3N + 9O


Moles (mol) = Mass (g) / Molar mass (g/mol)


Mass of Al(NO₃)₃ = 12 g

Molar mass of Al(NO₃)₃ = (27 + 14 x 3 + 16 x 9) g/mol

                                       = 213 g/mol

Mass of Al(NO₃)₃ = 12 g / 213 g/mol

                              = 0.0563 mol


The stoichiometric ratio between Al(NO₃)₃ compound and N atoms is 1 : 3.

Hence,

         the moles of N atoms = moles of Al(NO₃)₃ x 3

                                              = 0.0563 mol x 3

                                              = 0.1689 mol


According to the Avogadro constant,

              1 mol of substance = 6.02 x 10²³ particles


Hence, N atoms in the 12 g of Al(NO₃)₃ = 0.1689 mol x 6.02 x 10²³ mol⁻¹

                                                                   = 1.016778 x 10²³

                                                                   = 1.02 x 10²³


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