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ValentinkaMS [17]
3 years ago
5

Why is water important to cells

Chemistry
2 answers:
seropon [69]3 years ago
8 0
All cells need them to completly stay alive

Arturiano [62]3 years ago
6 0
Water is often called a solvent because it is key to so many processes where it acts as exactly that, a solvent. It helps to break waste and nutrients down in the cell so that they can be moved through the various membranes and natural filters in the body.
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Someone PLEASE help me I don’t remember this.
In-s [12.5K]

Answer: genotype: Ee phenotype: two small eyes.

genotype: RR'  phenotype: pink eyes

genotype: GB phenotype: green and blue splotches

genotype: cc phenotype:  straight

genotype: Tt phenotype:  has tail

genotype: Ss phenotype: sharp teeth

genotype: FF' phenotype: three toes

genotype: ww phenotype: white

genotype: YY phenotype: pointy

genotype: nn phenotype: two ears

genotype: Ll phenotype: long

Explanation: hope this helps (the uppercase letters are dominant genes. the lowercase letter are recessive genes. for a recessive gene to show up in a phenotype you need 2 lower case letters such as cc or ss. for a dominant gene to show up in phenotype you need either 1 or 2 uppercase letters such as Cc or SS. Codominant genes present both colors in the phenotypes i.e. a brown and white cow. incomplete dominance is when neither gene is dominant so a mix of the 2 are present in the phenotype i.e. a pink rose. A regulatory gene controls the expression of a gene

4 0
3 years ago
What is the percent composition of CuO if a sample of CuO with a mass of 62.5 g contains 12.5 g of oxygen (O) and 50 g of Cu
Arlecino [84]

Percent (%) Composition of CuO

Cu = 1 x 50g      - Multiply by one as there is one Cu

O = 1 x 12.5g      - Multiply by one as there is one O

CuO = 62.5g

% for Cu = 50g over 62.5 multiplied by 100 = 80%

% for O = 12.5g over 62.5 multiplied by 100 = 20%

Final Answer :

<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)

7 0
3 years ago
0.50 g of hydrogen chloride (HCl) is dissolved in water to make 4.0 L of solution. What is the pH of the resulting hydrochloric
svlad2 [7]

Explanation:

Given the mass of HCl is ---- 0.50 g

The volume of solution is --- 4.0 L

To determine the pH of the resulting solution, follow the below-shown procedure:

1. Calculate the number of moles of HCl given by using the formula:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}

2. Calculate the molarity of HCl.

3. Calculate pH of the solution using the formula:

pH=-log[H^+]

Since HCl is a strong acid, it undergoes complete ionization when dissolved in water.

HCl(aq)->H^+(aq)+Cl^-(aq)

Thus, [HCl]=[H^+]

Calculation:

1. Number of moles of HCl given:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}\\=0.50g/36.5g/mol\\=0.0137mol

2. Concentration of HCl:

Molarity of HCl=\frac{number of moles of HCl}{its molar mass}\\=\frac{0.0137 mol}{4.0 L} \\= 0.003425 M

3. pH of the solution:

pH=-log[H^+]\\=-log(0.003425)\\=2.47

Hence, pH of the given solution is 2.47.

3 0
3 years ago
Pls help it's about density ​
Vaselesa [24]
1. 100.67
2. 168.55
3. 2.747
So I’m not sure if 2 or 3 are right sorry
4 0
3 years ago
A student performed a chemical reaction in which 35 grams of hydrogen and 65 grams of oxygen reacted to form water. What is the
sergejj [24]

Answer:

The mass of the product is 73,06 g

Explanation:

The reaction to form water is:

2H2 + O2 ---> 2H2O

35 g     65 g

Molar mass H2 = 2g/m ---> I have 17,5 moles (35g / 2 g/m)

Molar mass O2 = 32g/m ---> I have 2,03 moles (65g / 32g/m)

2 moles of H2 __reacts with __ 1 mol O2

17,5 moles of H2 __ reacts with ___ (17,5 m . 1 m) / 2 m = 8,75 m

I have just 2,03 m of O2 and I need 8,75 m so O2 is my limiting reagent

1 mol of O2 ___ reacts with 2 moles H2

2,03 moles of O2 __ reacts with  (2,03 m . 2 m) / 1 m = 4,06 m

I have 17,5 moles of H2 and I need 4,06 m. H2 is my excess reagent

<u><em>"All operations are done with the limiting reagent"</em></u>

1 mol O2 are required____ to form 2 H2O

2,03 mol O2 are required __ to form (2,03m . 2m) / 1m = 4,06 m

Molar mass of water: 18 g/m

Mass of water ----> Molar mass . Moles water = 18 g/m . 4,06 m = 73,08g

8 0
3 years ago
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