Answer:
The answer is first one 1...
Answer:
Shortest distance = 0.1914 m
Explanation:
Given that,
Amplitude of the wave is 0.0957 m
Frequency of the wave is 3.75 Hz
Wavelength of the wave is 1.97 m
We need to find the shortest transverse distance between a maximum and a minimum of the wave.
The distance between maximum point in positive axis and the baseline is equal to amplitude.
Shortest distance = 2 A
D = 2 × 0.0957
D = 0.1914 m
So, the shortest transverse distance between a maximum and a minimum of the wave is 0.1914 m.
B. the distance the star is from Earth
Explanation:
The apparent magnitude of star is a function of its distance from the earth. It is one of the physical properties that is used to study a star.
The apparent magnitude of a star or other astronomical bodies is a measure of their brightness as seen from a location on the earth.
The apparent magnitude of a star depends on:
- Distance of the star from the location on earth.
- luminosity of the star
- the particles along the part of the star and earth that cuts off the light the earth receives.
learn more:
Star luminosity brainly.com/question/9084808
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Answer:
22.5 [m] is the distance from the person to the second post.
Explanation:
We can solve this problem graphically, first place the position of the person at the origin of x-y coordinates.
Then we locate the first post (1), tracing a line (or vector) with a length of 52 [m] from the origin of coordinates and with an angle of 37 ° north of East.
And for finding the distance from the second post (2) with respect to the person, we have to draw a line that has a length of 68 [m] and this line must be crossed with the y-axis and in the negative direction, in this way we can find the distance from the post with respect to the person.
Note: we can use set square and protractor to solve this problem
In the attached image we can find the graphic solution.
By this method of construction we can find the distance of post number 2 from the person and this is 22.55 [m] to the South