Force= distance/time
Maybe that formula will help
Answer:
a) t = 11.407 s, b) x = 175.66 m, v = c) v = 30.80 m / s
Explanation:
a) This is a kinematics exercise, let's write the equation of each vehicle
car
x = x₀ + v₀ t + ½ a t²
Let's fix our reference system at the point where the car is, indicate that the car stops from rest vo = 0
x₀ = v₀ = 0
we substitute
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
at the point where they are, their positions are equal
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.70
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 2.70 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.70 11.407
v = 30.80 m / s
Answer:
1317.4 m
Explanation:
We are given that
Angle=
Initial speed =
We have to find the horizontal distance covered by the shell after 5.03 s.
Horizontal component of initial speed=
Vertical component of initial speed=
Time=t=5.03 s
Horizontal distance =
Using the formula
Horizontal distance=
Horizontal distance=1317.4 m
Hence, the horizontal distance covered by the shell=1317.4 m
Answer:
Angular acceleration = -1.57 Rad/s^2
Number of revolutions = 800 revolutions
Explanation:
Mass = 1.15kg
diameter of the grinding wheel = 22.0cm
angular speed = 20 rev/s
1 Rev/s = 6.283 rad/s
20 Rev/s = 20 * 6.283 = 125.664 rad/s
Angular acceleration = Angular speed/ time taken for for the wheel rotation
Angular accleration = 125.664/80
Angular acceleration = -1.57 rad/s^2 (since the wheel is rotating counterclockwise)
number of revs = 0.5∝t²
number of revs = 0.5 * (1.57/2π) * 80²
number of revs = 800 revolutions
Answer:
No
Explanation:
We know that
Rationality in 3D flow is given as follows
If ω is equal to zero then flow will be irrotational and if ω is not equal to zero then flow will be rotational .
So if flow is ir-rotational it means that the component of ω in x-direction,in y-direction and in z-direction direction should be zero.
So it is not necessarily that 3D parallel flow will be irrotaional.
