The acceleration of the runner in the given time is 2.06m/s².
Given the data in the question;
Since the runner begins from rest,
- Initial velocity;
- Final velocity;
- Time elapsed;
Acceleration of the runner; 
<h3>Velocity and Acceleration</h3>
Velocity is the speed at which an object moves in a particular direction.
Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
To determine the acceleration of the runner, we substitute our given values into the equation above.
Therefore, the acceleration of the runner in the given time is 2.06m/s².
Learn more about Equations of Motion: brainly.com/question/18486505
The answer is true because A current carrying wire is surrounded by magnetic field
Answer:
the gas that escaped from the mixture contained the missing weight
Answer:
Velocity = 0.4762 m/s
Explanation:
Given the details for the simple harmonic motion from the question as:
Angular frequency, ω = 12 rad/s
Amplitude, A = 0.060 m
Displacement, y = 0.045 m
The initial Energy = U = (1/2) kA²
where A is the amplitude and k is the spring constant.
The final energy is potential and kinetic energy
K + U = (1/2) mv² + (1/2) kx²
where x is the displacement
m is the mass of the object
v is the speed of the object
Since energy is conservative. So, the final and initial energies are equal as:
(1/2) k A² = (1/2) m v² + (1/2) kx²
Using, ω² = k/m, we get:
Velocity:
![v=\omega\times \sqrt{[ A^2 - y^2 ]}](https://tex.z-dn.net/?f=v%3D%5Comega%5Ctimes%20%5Csqrt%7B%5B%20A%5E2%20-%20y%5E2%20%5D%7D)
![v=\omega\times \sqrt{[ {0.06}^2 - {0.045}^2 ]}](https://tex.z-dn.net/?f=v%3D%5Comega%5Ctimes%20%5Csqrt%7B%5B%20%7B0.06%7D%5E2%20-%20%7B0.045%7D%5E2%20%5D%7D)
<u>Velocity = 0.4762 m/s</u>
