Answer: 1.65m
Explanation:
Refractive index in terms of the depth of liquid is the ratio of the real depth to the apparent depth of the liquid i.e Refractive index =Real depth/apparent depth
Refractive index of water given = 1.33
Real depth is the measure of how deep is the liquid while apparent depth is the depth at the surface of the liquid.
Real depth = 2.2m
Apparent depth =?
Applying the formula above
Apparent depth =Real depth/refractive index
= 2.2/1.33
= 1.65m
Therefore, the circle of light that exits the surface of the water when that light shines in the middle of the night is 1.65m wide
Explanation:
it is almost zero .this is because the distance and the electrostatic force are inversely proportional
At position of maximum height we know that the vertical component of its velocity will become zero
so the object will have only horizontal component of velocity
so at that instant the motion of object is along x direction
while if we check the acceleration of object then it is due to gravity
so the acceleration of object is vertically downwards
so it is along y axis
so here these two physical quantities are perpendicular to each other
so correct answer would be
<em>C)At the maximum height, the velocity and acceleration vectors are perpendicular to each other. </em>