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3 years ago

An object is at rest on an inclined plane. In which direction does the static friction force act?

Physics

1 answer:

Liono4ka [1.6K]3 years ago

8 0

Gravity pulls on the object in the downward direction. The normal force to the inclined plane points in a direction perpendicular to the surface of the plane. Then for the object to be at rest, the frictional force must act parallel to the inclined plane, pointing in the upward direction.

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3 years ago

Which type of mirror would you use to cook a hot dog and why?

alexandr1967 [171]

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2 years ago

Peak wavelength of light coming from a star with a temp of 4300k

PSYCHO15rus [73]

from Wein's law

$\frac{k}{ \lambda_{max} } = T \\ \lambda_{max} = \frac{k}{T} \\ \lambda_{max} = \frac{3.898 \times {10}^{ - 3} }{4300} \\ = 9.065 \times {10}^{ - 7}$

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3 years ago

A striped billiard ball moves toward the right with speed 3 m/s. A solid billiard ball with the same mass moves toward the left

Helen [10]

Answer:

Final speed of striped ball is 3 m/s in left direction .

Explanation:

Given :

Two billiard ball with the same mass moves toward the left at the same speed 3 m/s .

Let , us assume right hand side direction to be positive and left hand side direction to be negative .

Also , let speed of ball after collision is (striped ball ) u and (solid ball) v .

It is also given that the collision is elastic .

Therefore , kinetic energy is conserved .

$\dfrac{m(3)^2}{2}+\dfrac{m(3)^2}{2}=\dfrac{mu^2}{2}+\dfrac{mv^2}{2}\\\\u^2+v^2=18$ ...... ( 1 )

Also , by conserving linear momentum .

We get :

$3m-3m=mu+mv\\u=-v$ ...... ( 2 )

Putting value of u from equation 2 to equation 1 .

We get :

$2v^2=18\\v=3\ m/s$

And , u = -3 m/s .

Therefore , final speed of striped ball is 3 m/s in left direction .

Hence , this is the required solution .

4 0

4 years ago

a) A unit of time sometimes used in microscopic physics is the shake. One shake equals 10–8 s. Are there more shakes in a second

lawyer [7]

Answer:

a) Yes, there are $10^8$ shakes in a second ( $1 s \frac{1 shake}{10^{-8}s}=10^8 shake$ ) in a year there are 31,536,000 seconds... that is 3.1536x $10^7$ ( $1year\frac{365 day}{1 year} \frac{24 h}{1 day} \frac{60 min}{1 h}\frac{60s}{1min}=3.1536 *10^7$ )

b) Note that the defined universe day will have 60*60*24=86400 universe seconds if the seconds are defined as normal seconds.

Also one universe day (or 86400 universe seconds) is equivalent to 1010 years. Now using a rule of three we can know the seconds that humans have existed.

$106 years * \frac{86,400 universe-seconds}{1,010 years}=9,067.728 s$

That is about 2 and half hours.

3 0

3 years ago