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Nadya [2.5K]
3 years ago
14

An object is at rest on an inclined plane. In which direction does the static friction force act?

Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Gravity pulls on the object in the downward direction. The normal force to the inclined plane points in a direction perpendicular to the surface of the plane. Then for the object to be at rest, the frictional force must act parallel to the inclined plane, pointing in the upward direction.

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An applicable analogy for part of this activity: The most direct route between San Diego, California, and Caribou, Maine, is abo
PtichkaEL [24]

Answer:

Total time spend = 48.18 hours (Approx)

Explanation:

Given:

Total distance = 5,300 km

Average speed = 110 km / h

Find:

Total time spend

Computation:

Time = Distance / speed

Total time spend = Total distance / Average speed

Total time spend = 5,300 / 110

Total time spend = 48.18 hours (Approx)

3 0
4 years ago
The average intensity of sunlight at the top of the earth's atmosphere in 1390 w/m2. what is the maximum energy that a 34-m x 46
slavikrds [6]
Panel surface area =34m×46m=1,564m^2
total power =1564m^2×1390w/m^2
=2173960watts
now you must calculate total energy.
Energy = power×Time
However time must be in seconds so we multiply 2hrs×60min×60s=7200seconds
7200s×2173960w =15,652,512,000 joules of energy
7 0
3 years ago
One carpenter builds 1/5 of a house in 3/4 of a day and the other builds 2/5 of a house in the same amount of time. How many hou
AlladinOne [14]

Answer:

4/5 houses

Explanation:

The speed of the first carpenter is:

(1/5 house) / (3/4 day) = 4/15 house/day

The speed of the second carpenter is:

(2/5 house) / (3/4 day) = 8/15 house/day

Together, their combined speed is:

4/15 house/day + 8/15 house/day = 12/15 house/day

= 4/5 house/day

Per day, the two carpenters build 4/5 of a house.

4 0
3 years ago
If you cut a permanent magnet into four pieces,
lora16 [44]

you would have C) two north poles and two south poles

8 0
3 years ago
Two particles with charges +6e and -6e are initially very far apart (effectively an infinite distance apart). They are then fixe
JulijaS [17]

Answer:

\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}\ J.

Explanation:

Given charges are:

\rm q_1 = +6e.\\q_2 = -6e.

The electric potential energy of a charge due to the electric field of another charge is given by

\rm EPE=\dfrac{kq_1q_2}{r}.

where,

  • k = Coulomb's constant, having value = \rm 9\times 10^9\ Nm^2/C^2.
  • r = distance between the charges.

When the charges are infinite distance apart, \rm r = \infty,

\rm EPE_{initial} = \dfrac{kq_1q_2}{r}=0\ J.

When the charges are \rm 5.61\times 10^{-12}\ m apart, \rm r=5.61\times 10^{-12}\ m,

\rm EPE_{final}=\dfrac{kq_1q_2}{r}\\=\dfrac{(9\times 10^9)\times (+6e)\times (-6e)}{5.61\times 10^{-12}}\\=-5.775\ e^2\times 10^{22}.

Here, e is the charge on one electron, such that, \rm e = -1.6\times 10^{-19}\ C.

Therefore,

\rm EPE_{final}=-5.775\times (-1.6\times 10^{-19})^2\times 10^{22} = -1.478\times 10^{-15}\ J.

Thus,

\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}-0=-1.478\times 10^{-15}\ J.

4 0
3 years ago
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