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vazorg [7]
3 years ago
15

3. How many moles of HCl are present in 3.70 L of a 2.33 M HCl solution?

Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

8.6 mol

Explanation:

number of moles = molar concentration x volume in litre

number of moles = 2.33 M x 3.70 L = 8.6 mol

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Label the following changes as Physical or
Leno4ka [110]

Answer:

17

Two clear liquids mix and form a

white solid

18.chemical

A pot of water begins to

boil

19.Physical

the rest im usure on.

5 0
3 years ago
The Society of Automotive Engineers has established an accepted numerical scale to measure the viscosity of motor oil. For examp
natta225 [31]

Answer:

Most viscous to least viscous: (c)> (b)> (a)

Explanation:

For hydrocarbons, viscosity increases with increasing molar mass. Because increasing molar mass signifies increase in number of electrons in molecules.

We know that in non-polar hydrocarbons, only van der waal intermolecular force exists. Van der waal force is proportional to number of electrons in a molecule.

Therefore with increasing molar mass, van der waal force increases. hence molecules gets more tightly bind with each other resulting increase in viscosity.

Here molar mass order : (c)> (b)> (a)

Therefore viscosity order : (c)> (b)> (a)

5 0
3 years ago
Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

8 0
1 year ago
Which of the following IS a valid piece scientific evidence?
Vanyuwa [196]

im sorry it doesn't show

5 0
3 years ago
The mass of an atom is measured in a unit named the<br> ____. fill in the blank please helpppp
Volgvan

Answer: amu

Explanation: it stands for atomic mass unit and it is the measurement that’s used to measure the mass of atoms

5 0
3 years ago
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