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tensa zangetsu [6.8K]
3 years ago
7

Jenny and Betty are having a great time at Busch Gardens riding the Ubanga Banga bumper cars. Jenny, who is traveling southward

in her bumper car, aims her car toward Betty, who is traveling northward in her bumper car. The cars collide and briefly come to a stop.
What is the direction of the acceleration of Jenny's car during the collision?

Southward or Northward?
Physics
2 answers:
Alex777 [14]3 years ago
6 0

Jenny is traveling southward.  In order to stop, she needs a northward acceleration.


A better way to say it:

Jenny is traveling southward in her bumper car, so the direction of her velocity is south.  In order to reduce her velocity to zero, a velocity of equal magnitude but directed north must be added to it.  Then the change in velocity is positive northward, and the change in velocity per unit time is acceleration.

max2010maxim [7]3 years ago
6 0

Answer:

The direction of the acceleration of Jenny's car during the collision is Northward.

Explanation:

Newton's Third Law is also known as the Principle of action and reaction. This law indicates that “Every action has an equal reaction but in the opposite direction” This means that when a body exerts a force (action) on another, it responds with a force of equal magnitude although opposite direction (reaction). Then this law explains that forces always occur in the form of pairs: an action and a reaction.

This law applies in this case. Jenny, who travels south in her bumper car, points her car at Betty. When crashing and stopping, the force received and its acceleration went north due to the pair of action (in this case the trip south in the bumper car) and reaction (the car responds with a force of equal magnitude although opposite direction, the North).

Then, the direction of the acceleration of Jenny's car during the collision is Northward.

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Why can light microscopes produce images in their natural color
Fiesta28 [93]

Answer:

The electron microscopes  are uses the electron to produce the image of the any object.The area where the electron passes then that area  appeaser white but on the other hand where the electron does not pass that area appears black.But this does not give any information about the color of light it shows only white and black areas.We also know that color is the property of photons ( light).So the microscopes does not produce color of the image.

6 0
3 years ago
A force of 6.0 N gives a 2.0 kg block an acceleration of 3.0
Semenov [28]

Explanation:

The Net Force of the object can be written by:

Fnet = ma

where m is the mass of the object in <em>kg</em>

a is the acceleration of the object in <em>m/s^2</em>

Hence by applying the formula we get:

Fnet = (2.0)(3.0)

= 6N

We also know that Net force is also the sum of all forces acting on an object. In this case Friction and the Pushing Force is acting on the object. Hence we can write that:

Fnet = Pushing Force + (-Friction)

6N = 6N - Friction

Friction = 0N

Hence the<u> </u><u>f</u><u>orce of friction is 0N.</u>

7 0
3 years ago
__________ is/are formed between two air masses that have different temperatures. (4 points) A: Wind B:The jet stream C:Clouds D
lidiya [134]
The answer is B: the jet stream.


8 0
3 years ago
Read 2 more answers
NEED ASAP PLEASE
miskamm [114]

Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.

6 0
3 years ago
# A cheetah can start from rest and attain the velocity 72km/h in 2 seconds. Calculate the acceleration of cheetah
yan [13]

Answer:

<h2>10 \: m/s ^2</h2><h2 />

Explanation:

Solution,

When a certain object comes in motion from rest, in the case, initial velocity = 0 m/s

Initial velocity ( u ) = 0 m/s

Final velocity ( v ) = 72 km/h ( Given)

We have to convert 72 km /h in m/s

72 \: km \: per \: hour

= 72 \times  \frac{1000}{60  \times 60}

= 20 m/s

Final velocity ( v ) = 20 m/s

Time taken ( t ) = 2 seconds

Acceleration (a) = ?

Now,

we have,

a =  \frac{v - u}{t}

a =  \frac{20 - 0}{2}

a =  \frac{20}{2}

a = 10 m/s ^2

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
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