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murzikaleks [220]
3 years ago
7

A force of 50 N is used to move a footstool 3 m. How much work is done?

Physics
1 answer:
vaieri [72.5K]3 years ago
5 0

The work done is 150 joules

Explanation:

Work occurs when a force (F) acts on an object to move it some

distance (d) from the start point

→ Work done = F × d

The S.I unit of work is Joule

A force of 50 N is used to move a footstool 3 m

→ F = 50 N

→ d = 3 m

→ Work done = F × d

Substitute the values of F and d in the rule

→ Work done = 50 × 3 = 150 joules

The work done is 150 joules

Learn more

You can learn more bout work done in brainly.com/question/9100769

#LearnwithBrainly

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A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia
Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0
3 years ago
Calculate the force exerted on this test dummy with a mass of 75 kg hits an air bag accelerating at 12 m/s2.
maksim [4K]

Answer: 900

Explanation: Force equals mass x acceleration F=M×A

3 0
3 years ago
A motorcycle traveling at a speed of 44.0 mi/h needs a minimum of 44.0 ft to stop. If the same motorcycle is traveling 79.0 mi/h
Tasya [4]

Answer:

141.78 ft

Explanation:

When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.

Calculating the acceleration using one of Newton's equations of motion:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 44 mi/h\\\\s = 0.00833 mi\\\\=> 0^2 = 44^2 + 2 * a * 0.00833\\\\=> 1936 = -0.01666a\\\\a = -116206.48 mi/h^2 or -14.43 m/s^2

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 79 mi/h\\\\a = -116206.48 mi/h\\\\=> 0^2 = 79^2 + (2 * -116206.48 * s)\\\\6241 = 232412.96s\\\\s = \frac{6241}{232412.96} \\\\s = 0.0268531 mi = 141.78 ft

The minimum stopping distance is 141.78 ft.

4 0
3 years ago
archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken
Cerrena [4.2K]
Answer:

Acceleration = 45m/s^2
Time = 2 s

Explanation:

6 0
3 years ago
______is the rate of change in velocity.
shepuryov [24]

Answer:

Acceleration

Explanation:

Acceleration is the rate of change in velocity

speed is how fast an object is moving

Velocity is how fast an object is moving in the particular direction

pls mark me brainliest

6 0
3 years ago
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