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2 years ago

A force of 50 N is used to move a footstool 3 m. How much work is done?

Physics

1 answer:

vaieri [72.5K]2 years ago

5 0

The work done is 150 joules

Explanation:

Work occurs when a force (F) acts on an object to move it some

distance (d) from the start point

→ Work done = F × d

The S.I unit of work is Joule

A force of 50 N is used to move a footstool 3 m

→ F = 50 N

→ d = 3 m

→ Work done = F × d

Substitute the values of F and d in the rule

→ Work done = 50 × 3 = 150 joules

The work done is 150 joules

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Explanation:

In the image attached with this answer are shown the given options from which only one is correct.

The correct expression is:

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Because, if we derive velocity $v_{t}$ with respect to time $t$ we will have acceleration $a$ , hence:

$m \frac{d}{dt}v_{(t)}=m.a$

Where $m$ is the mass with units of kilograms ( $kg$ ) and $a$ with units of meter per square seconds $\frac{m}{s}^{2}$ , having as a result $kg\frac{m}{s}^{2}$

The other expressions are incorrect, let’s prove it:

$\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)}$ This result has units of $kg\frac{m}{s}$

$m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m$ This result has units of $kg$

$m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C$ This result has units of $kgm^{2}$ and $C$ is a constant

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