A boat is headed due north on a river that's flowing directly east. What is the general direction of travel for this boat with r
2 answers:
Answer:
It must be moving at an angle with East towards North
Explanation:
As we know that boat headed towards North while river is flowing towards East
So here the resultant velocity of boat is vector sum of velocity of river and velocity of boat.
So we will find the vector resultant as
here we know
= velocity of boat towards North
= velocity of river towards East
now if we add two vectors along North and and east then the resultant must be between North and East so the boat will move at some angle with East towards North
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Answer:
Centripetal acceleration = 0.79 m/s²
Explanation:
<u>Given the following data;</u>
Radius, r = 2.6 km
Time = 360 seconds
<em><u>Conversion:</u></em>
2.6 km to meters = 2.6 * 1000 = 2600 meters
To find the magnitude of centripetal acceleration;
First of all, we would determine the circular speed of the car using the formula;
Where;
- r represents the radius and t is the time.
Substituting into the formula, we have;
Circular speed, V = 45.38 m/s
Next, we find the centripetal acceleration;
Mathematically, centripetal acceleration is given by the formula;
Where;
- V is the circular speed (velocity) of an object.
- r is the radius of circular path.
Substituting into the formula, we have;
<em>Centripetal acceleration = 0.79 m/s²</em>
Answer:
The water is flowing at the rate of 28.04 m/s.
Explanation:
Given;
Height of sea water, z₁ = 10.5 m
gauge pressure, = 2.95 atm
Atmospheric pressure, = 101325 Pa
To determine the speed of the water, apply Bernoulli's equation;
where;
P₁ =
P₂ =
v₁ = 0
z₂ = 0
Substitute in these values and the Bernoulli's equation will reduce to;
where;
is the density of seawater = 1030 kg/m³
Therefore, the water is flowing at the rate of 28.04 m/s.