A boat is headed due north on a river that's flowing directly east. What is the general direction of travel for this boat with r
2 answers:
Answer:
It must be moving at an angle with East towards North
Explanation:
As we know that boat headed towards North while river is flowing towards East
So here the resultant velocity of boat is vector sum of velocity of river and velocity of boat.
So we will find the vector resultant as
here we know
= velocity of boat towards North
= velocity of river towards East
now if we add two vectors along North and and east then the resultant must be between North and East so the boat will move at some angle with East towards North
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Answer:
a) 0 metres
b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s
c) 20 m/s
Explanation:
a) <em>Formula of displacement= velocity x time</em>
time=40 s
velocity =0 m/s
∴ displacement= 0 x 40 = 0 m
Magnitude of displacement is 0 m
b) The increase in velocity shows that there has been acceleration.
c) The average velocity of the car is = {initial velocity + final velocity}
=
=20
Therefore, the magnitude of the average velocity of the car is 20 m/s
Answer:
1.41 m/s^2
Explanation:
First of all, let's convert the two speeds from km/h to m/s:
Now we find the centripetal acceleration which is given by
where
v = 12.8 m/s is the speed
r = 140 m is the radius of the curve
Substituting values, we find
we also have a tangential acceleration, which is given by
where
t = 17.0 s
Substituting values,
The two components of the acceleration are perpendicular to each other, so we can find the resultant acceleration by using Pythagorean theorem: