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nasty-shy [4]
4 years ago
5

A boat is headed due north on a river that's flowing directly east. What is the general direction of travel for this boat with r

espect to the land?
Physics
2 answers:
nlexa [21]4 years ago
8 0

Answer:

It must be moving at an angle \theta with East towards North

Explanation:

As we know that boat headed towards North while river is flowing towards East

So here the resultant velocity of boat is vector sum of velocity of river and velocity of boat.

So we will find the vector resultant as

\vec v = \vec v_b + \vec v_r

here we know

\vec v_b = velocity of boat towards North

\vec v_r = velocity of river towards East

now if we add two vectors along North and and east then the resultant must be between North and East so the boat will move at some angle \theta with East towards North

LenKa [72]4 years ago
3 0
The answer would be northeast
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How would improvement in use of renewable energy sources impact climate change sea-level rise?
bonufazy [111]

Answer:

Almost immeasurably small.

Explanation:

The STORY is that humans are BAD for the environment and have caused a HUGE change in the amount of CO₂ in the atmosphere.

Let's look at the reports and draw our own conclusions.

Current CO₂ levels are 409.8 parts per million (PPM)

at the beginning of the Industrial revolution in the 1700's, the presumed beginning of the huge increase in CO₂ the level was about 280 PPM

For perspective lets assume we capture the whole atmosphere and squish it down to 2400 one liter bottles of air

That's 100 cases of 24 bottles per case.

We now separate all the air components into their own bottles

Nitrogen is 78% of our air, so we subtract 78 cases from our 100 leaving 22

Subtracting Oxygen at 21% of air leaves 1 case of liter bottles left

Of those 24 bottles, Argon makes up 0.93% of air so we subtract 22 bottles

The remaining two bottles contain all of the other gasses in our air, One of those bottles contains CO₂.

If we take the CO₂ levels from the 1700's at about 280 PPM as a baseline and assume ALL of the increase is human caused, that is (410 -280) / 280 = 46 % of the total.

The human caused addition of CO₂ would be 460 mililiters out of 2400 liters over the course of 250 years 

The claim is, that less than half of a liter of CO₂ out of 2400 liters of air is responsible for heating not only the gas in all the other bottles but also the surface of the earth itself.

Personally, it boggles my mind.

And it says NOTHING of a far more powerful greenhouse gas that is far more prevalent in the atmosphere...water vapor.

Water vapor is about 1% of air at sea level and about 0.4% overall. It was not considered in the above analysis because water vapor can condense out and is not a constant in the air.

Notice that there is about 100 times the amount of water vapor in the air as compared to CO₂. Water vapor also has between 4 and 8 times the greenhouse effect that CO₂ does.

Makes one wonder why we choose to pick on CO₂.

7 0
3 years ago
A dvd drive has a maximum speed of 72000 revolutions per minute. if a dvd has a diamter of 12 what is the linear speed
Brilliant_brown [7]
The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
P=2\pi.R
Know recall that:
v=\frac{d}{t}
We now need to know how much distance is traveled during a minute or 60 seconds:
D=7200\times 2\pi\times R
Finally we divide this result with t=60 seconds:
v=\frac{7200\times2\pi\times R}{60}
\\
R=\frac{12}{2}=6

v\approx 4523.89 \frac{units}{second}
Where the distance units were named units as the length unit is not specified in this exercise.<span />
7 0
4 years ago
If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d
Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

v_{i}=-44.5m/s\\v_{f}=55.5m/s

Now we need to find the initial momentum

So

P_{1}=m*v_{i}

Substitute the given values

P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s

Now for final momentum

P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s

So the change in momentum is given as:

ΔP=P₂-P₁

=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s

ΔP=20 kg.m/s

3 0
4 years ago
The density of blood is 1.05 kg/m3, find the mass of a bag of blood for a transfusion, if the volume is 1.5 m3.
hoa [83]

(1.5 m^3) • (1.05 kg/m^3) = 1.575 kg.  That's quite a bag you've got there !  1 m^3 is like 264 gallons of blood.  Hope the poor patient survives the transfusion. Also, the actual density of blood is around 1.05 g/cm^3, or 1050 kg/m^3. The blood they're giving the guy in this question is about 18% less dense than the AIR in his hospital room, and they're pumping 264 gallons of it into him. Maybe THAT'S his whole problem.

6 0
3 years ago
Read 2 more answers
At 1.70 atm, a sample of gas takes up 4.25L. If the pressure in the gas is increased to 2.40 atm, what will the new volume be?
ozzi

Answer:

This question is an example of Boyle's gas law which states that the pressure of a given mass of a gas is inversely proportional to its volume at a constant temperature. The formula for this gas law is:

P1·V1 = P2·V2

P1 = initial pressure = 1.7 atm

V1 = initial volume = 4.25 L

P2 = final pressure = 2.4 atm

V2 = final volume = ?

Rearrange the formula to isolate V2. Substitute the known data and solve.

V2 = P1·V1/P2

V2 = 1.7 atm·4.25 L/2.4 atm = 3.0 L to two significant figures

The new volume will be ~3.0 L.

Explanation:

3 0
3 years ago
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