1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
3 years ago
7

Which state of matter has the following physical properties:

Chemistry
1 answer:
Nadya [2.5K]3 years ago
6 0
The state of matter is Liquid
Explanation:

The density of water is roughly 1 gram per milliliter but, this changes with temperature or if there are substances dissolved in it. Ice is less dense than liquid water which is why your ice cubes float in your glass. As you might expect, water density is an important water measurement.
You might be interested in
What is the pH of a solution with a concentration of 4.7 × 10-4 molar H3O+?
wlad13 [49]
The pH of a liquid substance is calculated through the equation,
                                       pH = -log[H3O+]
Substituting the given concentration of the hydronium ion to the equation above,
                                        pH = -log[4.7x10^-4 M]
The value of pH is equal to 3.33. Thus, the pH of the solution is approximately 3.33. 
3 0
3 years ago
7.01*10^23 sulfur atoms is equal to______mol<br> Help please
lana66690 [7]
The answer is 1.164451827 moles
4 0
3 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
Marina86 [1]

Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

The differential equation for decay is

\frac{dA}{dt}= kA

\Rightarrow \frac{dA}{A}=kdt

Integrating both sides

ln A= kt+c₁

\Rightarrow A= e^{kt+c_1}

\Rightarrow A=Ce^{kt}         [e^{c_1}=C]

The initial condition is A(0)= A₀,

\therefore A_0=Ce^{0.k}

\Rightarrow C=A_0

\therefore A=A_0e^{kt}.........(1)

Given that the Pb_{209}  has half life of 3.3 hours.

For half life A=\frac12 A_0 putting this in equation (1)

\frac12A_0=A_0e^{k\times3.3}

\Rightarrow ln(\frac12)= 3.3k     [taking ln both sides, ln \ e^a=a]

\Rightarrow k=\frac{ln \frac12}{3.3}

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

\therefore 0.2=1e^{(-0.21)\times t}

\Rightarrow e^{-0.21t}=0.2

\Rightarrow -0.21t= ln(0. 2)

\Rightarrow t= \frac{ln (0.2)}{-0.21}

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

3 0
3 years ago
PLEASE HELP I got this wrong on an exam but got it wrong and i don’t know why!
lord [1]

Answer:

D.5,55cm+/-0,005cm

Explanation:

so this is the answer

5 0
3 years ago
IDENTIFY THE NUMBER OF SIGNIFICANT FIGURES IN EACH OF THESE MEASUREMENTS OF AN OBJECT: 76.47 AND 76.59
murzikaleks [220]

Answer:

they both have 4 sig figs:)

Explanation:

8 0
3 years ago
Other questions:
  • which diagram best illustrates the ion-molecule attractions that occur when the ions of NaCl(s) are added to water
    6·1 answer
  • Calculate the density of a sample if the mass is 2.98g and the volume is 2.12l
    10·1 answer
  • What information is given in a chemical formula?
    15·1 answer
  • Calculate the final temperature of a sample of carbon dioxide of mass 16.0 g that is expanded reversibly and adiabatically from
    13·1 answer
  • 80 liters of oxygen is collected over water at 50.0 degrees Celsius. The atmospheric pressure during the collection was 96.00 kp
    14·1 answer
  • What is the molarity of 5.39 grams of CaCl2 dissolved in 609 mL of water? (molar mass = 110.98 g/mol)
    5·1 answer
  • Can someone please describe what they’re seeing in this picture?
    10·1 answer
  • What is the basic principle that is used during the during the structures of compounds​
    9·1 answer
  • Worth 100 points plus ill mark brainliest
    7·1 answer
  • The weight of an object never changes.<br><br><br> A. True B. False
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!