Three classes: 28×3=84 students
8 test tubes per student: 84× 8= 672
hope this helps!
The final volume V₂=4.962 L
<h3>Further explanation</h3>
Given
T₁=20 + 273 = 293 K
P₁= 1 atm
V₁ = 4 L
T₂=100+273 = 373 K
P₂=780 torr=1,02632 atm
Required
The final volume
Solution
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
V₂=(P₁V₁T₂)/(P₂T₁)
V₂=(1 x 4 x 373)/(1.02632 x 293)
V₂=4.962 L
Answer:
Ok Hold up. I will answer after I think of question
Explanation:
Answer: A. The variable c
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Explanation:
Q = heat transferred
m = mass
c = specific heat
= delta T = change in temperature
