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kaheart [24]
4 years ago
6

When comparing fifteenth- and twenty-first- century forensic-science tools available for document examination, which modern tool

would not have been available in the fifteenth century?
Chemistry
1 answer:
Whitepunk [10]4 years ago
7 0
Many forensic tools that are available now were not available in the 15th century. For starters, microscopes did not exist in the fifteenth century so no finer details could be examined on documents. Now, there exist many different types of microscopes. Moreover, with new methods such as carbon dating, the age of different documents may be determine. 
All of these differences from the fifteenth century have helped forensic analysts better analyze documents than analysts in the past could.
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Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. (1.8 x 1
slamgirl [31]

Answer : The answer is, 0.2\times 10^{-4}

Explanation :

Scientific notation : It is defined as the way or representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.

For example : 8000 is written as, 8.0\times 10^3  in this notation, the significant figure is, 1 but 0.8\times 10^4  in this notation, the significant figures are, 2

The given problem are :

\frac{1.8\times 10^{-2}}{9\times 10^2}=0.2\times 10^{-4}

According to the divide and multiplication rules of scientific figures, the final answer is only as precise as the value with the least number of significant figures.

Hence, the answer is, 0.2\times 10^{-4}

6 0
3 years ago
Read 2 more answers
Calculate the percent composition by mass of each element in Al(OH)3. Use at least three significant figures.
motikmotik

Answer:

nope nope nope nope nope nope nope nope

7 0
3 years ago
Read 2 more answers
Mass of 0.432 moles of C8H9O4?
Fiesta28 [93]
Find one mole
8 C = 8 * 12 = 96
9 H = 1 * 9 = 9
4 O = 4 *16 = 64
Total = 169 

1 mol = 169 grams.
0.432 mol = x

1/0.432 = 169/x
x = 0.432 * 169
x = 73.0 grams
7 0
3 years ago
Read 2 more answers
Which is an element?<br> A: H20<br> B: NaCl<br> C: Mg<br> D: CO
Talja [164]
The answer is option D "CO." Co also known as Cobalt is the 27th element on the periotic table. It was discovered in <span>1735, it's boiling point is 3200 k.</span>

Atomic mass: 58.9332
Protons: 27
Neutrons: 32
Electrons: 27

Hope this helps!

3 0
3 years ago
Read 2 more answers
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
4 years ago
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