Hi there!
This collision is an example of an inelastic collision since kinetic energy is lost from the collision.
We can represent this using the conservation of momentum formula:
m1v1 + m2v1 = m1vf + m2vf
Where:
m1 = blue ball
m2 = green ball
We know that the final velocity of the blue ball is 0, so:
m1v1 + m2v1 = m2vf
Rearrange to solve for the speed of the green ball:
(m1v1 + m2v1)/m2 = vf
Plug in given values:
((0.15 · 3) + (0.15 · 2)) / 0.15 = 5 m/s
Answer:
See below
Explanation:
rho = R A/l R = resistance A = cross sectional area l = length
Newton’s Thrid Law, which states that for every reaction there is an opposite reaction.
Answer:
2800000J
Explanation:
Parameters given:
Mass = 920kg, weight = 920 * 9.8 = 9016N
Distance = 310m
Angle of inclination = 6.5°
Work done is given as :
W = F*d*cosA
Where A = angle of inclination
W = (9016 * 310 * cos6.5)
W = 2776993.59J
In 2 significant figures, W = 2800000J
Answer:
<em>The correct option is 1. 720 m</em>
Explanation:
<u>Projectile Motion</u>
When an object is launched in free air (no friction) with an initial speed vo at an angle 
, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.
The initial velocity has these components in the x and y coordinates respectively:
And we know the plane has an altitude of 600 m, so the package will reach ground level when:
The vertical distance traveled is given by:
We'll set up an equation to find the time when the package lands
Solving for t, we find only one positive solution:
The horizontal distance is:
The correct option is 1. 720 m
