It can be disproved with <span>one reproducible experiment.</span>
Given:
The mass of the truck is m1 = 3162 kg
The speed of the truck is v1i = 12 m/s in East
The mass of the parked car is m2 = 510 kg
The speed of car is v2i = 0 m/s
The speed of car after collision is v2f = 24 m/s in East
To find the speed of the truck after collision.
Explanation:
The final velocity of the truck will be
Thus, the speed of the truck after collision is 8.129 m/s
F = 2820.1 N
Explanation:
Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as
Fnet = ma = 0 (a = 0 no sliding)
= F - mgsin15°
= 0
or
F = mgsin15°
= (120 kg)(9.8 m/s^2)sin15°
= 2820.1 N
Answer:
600Joules
Explanation:
The energy stored by this battery is calculated using the energy formula;
E = Q× v
Where E is energy
Q is the charge
v is voltage
Hence E = 50 × 12 = 600Joules
Note Q = 12 ampere minute
That part of the wave is called a compression.
