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PIT_PIT [208]
2 years ago
15

A spring hangs at rest from a support. If you suspend a 0.46 kg mass from the spring it elongates 0.79m.

Physics
1 answer:
Fudgin [204]2 years ago
4 0

a. The restoring force in the spring has magnitude

F[spring] = k (0.79 m)

which counters the weight of the mass,

F[weight] = (0.46 kg) g = 4.508 N

so that by Newton's second law,

F[spring] - F[weight] = 0   ⇒   k = (4.508 N) / (0.79 m) ≈ 5.7 N/m

b. Using the same equation as before, we now have

F[weight] = (0.75 kg) g = 7.35 N

so that

(5.7 N/m) x - 7.35 N = 0   ⇒   x = (7.35 N) / (5.7 N/m) ≈ 1.3 m

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A train travels 70 kilometers in 1 hours, and then 63 kilometers in 2 hours. What is its average speed?
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3 0
3 years ago
What is the acceleration of the the object during the first 4 seconds?
AVprozaik [17]

Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

6 0
2 years ago
Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart
almond37 [142]

The force exerted on the cart 2 during the collision is 2 N.

The given parameters:

  • <em>Mass of cart 1 = m1 = 1 kg</em>
  • <em>Mass of cart 2 = m2 = 2kg</em>
  • <em>Force applied on cart 1 = 2 N</em>

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.

F_1 = -F_2

F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N

Thus, the force exerted on the cart 2 during the collision is 2 N.

Learn more about Newton's third law of motion here: brainly.com/question/13874955

5 0
2 years ago
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