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kvasek [131]
3 years ago
15

The emission of the light waves in the lasers allows them to overlap properly to create larger waves, which means that _____ ove

rlap.
A. the waves do not
B. the troughs of one wave and the crests of another
C. identical parts of the two waves
D.
only fifty percent of one wave and another wave
Chemistry
1 answer:
Vikentia [17]3 years ago
5 0
The emission of the light waves ..................... which means that THE TROUGHS OF ONE WAVE AND THE CREST OF ANOTHER overlap.
When the trough and the crest of wave overlap, it results in constructive interference and the amplitude of the two waves are added together  to form a larger amplitude.<span />
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A student was given a piece of metal with a mass of 85.0 g. She placed it
Anastasy [175]

Answer:

22mL

Explanation:

6 0
3 years ago
What is the cell potential for the reaction mg(s+fe2+(aq?mg2+(aq+fe(s at 77 ?c when [fe2+]= 3.40 m and [mg2+]= 0.210 m . express
Galina-37 [17]
First, you need to calculate the standard cell potential using standard reduction potential from a textbook or online. Since Mg becomes Mg+2, magnesium is being oxidized because it is losing electrons, you need to flip its potential

Fe+2 + 2e- --> Fe                  potential= -0.44
Mg+2 + 2e- --> Mg                potential= -2.37


Cell potential= (-0.44) + (+2.37)= 1.93 V

Now, you need to use Nernst formula to get the answer. I have attached a PDF with the work.
Download pdf
8 0
3 years ago
If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?
kvv77 [185]

Answer:

<h2>The answer is 14.29 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

P(\%) =  \frac{0.1}{0.7}  \times 100 \\  = 14.285714...

We have the final answer as

<h3>14.29 %</h3>

Hope this helps you

4 0
3 years ago
In your own words, what was the purpose of this lab? |
dalvyx [7]

Answer:

answer depends on what lab you are talking about

Explanation:

there are millions of labs out there

7 0
3 years ago
Read 2 more answers
When copper is bombarded with high-energy electrons, X rays are emitted. Calculate the energy (in joules) associated with the ph
Scrat [10]

Answer:

E = 12.92 × 10^(-16) J

Explanation:

Formula for energy is;

E = hc/λ

Where;

h is Planck's constant = 6.63 x 10^(-34) J.s

c is speed of light = 3 × 10^(8) m/s

λ is wavelength = 0.154 nm = 0.154 × 10^(-9) m

E = (6.63 x 10^(-34) × 3 × 10^(8))/(0.154 × 10^(-9))

E = 12.92 × 10^(-16) J

6 0
3 years ago
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