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My name is Ann [436]
3 years ago
5

You're carrying a 3.0-m-long, 24 kg pole to a construction site when you decide to stop for a rest. You place one end of the pol

e on a fence post and hold the other end of the pole 35 cm from its tip. How much force must you exert to keep the pole motionless in a horizontal position?
Physics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

F=133N

Explanation:

From the question we are told that:

Length l=3.0m

Mass m=24kg

Distance from Tip d=35cm

Generally, the equation for Torque Balance is mathematically given by

mg(l/2)=F(l-d)

2*9.81(3/2)=F(3-35*10^-2)

Therefore

F=133N

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Estimate the electric field at a point 2.40 cm perpendicular to the midpoint of a uniformly charged 2.00-m-long thin wire carryi
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Explanation:

Hi!

The perpendicular distance 2.4cm, is much less than the distance to both endpoints of the wire, which is aprox 1m. Then the edge effect is negligible at this field point, and we can aproximate the wire as infinitely long.

The electric filed of an infinitely long wire is easy to calculate. Let's call z the axis along the wire. Because of its simmetry (translational and rotational), the electric field E must point in the radial direction,  and it cannot depende on coordinate z. To calculate the field Gauss law is used, as seen in the image, with a cylindrical gaussian surface. The result is:

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