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3 years ago

Which of the following is an example of distance equaling displacement?

Physics

1 answer:

AleksandrR [38]3 years ago

3 0

Answer:

Explanation:

The student had displaced their in the class when she left. The phone is what's displaced and student leaving equals distance.

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elaborate on the difference between a chemical change and a physical change. a) a physical change is irreversible where as a che

lozanna [386]

I think the correct answer from the choices listed above is option D. The difference between a chemical change and a physical change is lies in the fact that a physical change does not break any bonds while a chemical change does form new substances. Hope this answers the question.

4 0

3 years ago

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A 80 mW laser beam is polarized horizontally. It then passes through two polarizers. The axis of the first polarizer is oriented

inn [45]

The E(incident) for the first polarizer is E(incident)=-76.1930384332

The E(incident) for the second polarizer is E(incident)=12.340115991

Explanation:

Solving the problem:

Given

Transmitted data = 80 mW

First polarizer= 30 degree

Second polarizer= 60 degree

We have the formula,

E (transmitted) = E (incident)cos()

1. Through the first polarizer

E (transmitted) = E (incident)cos()

80=E(incident) cos(60 degree) (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 60 degree

E(incident)=-76.1930384332

The E(incident) for the first polarizer is E(incident)=-76.1930384332

2. Through the first polarizer

We have the formula,

E (transmitted) = E (incident)cos()

80=E(incident) cos(30 degree) (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 30 degree

E(incident) =12.340115991

The E(incident) for the second polarizer is E(incident)=12.340115991

4 0

3 years ago

The flow of electrons in a circuit follows a path from the negative terminal of the battery to the positive terminal

SVEN [57.7K]

Answer:

No it's not true electric grow from Positive terminal to negative terminal

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2 years ago

What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward

Yuri [45]

Answer:

$q = 2.067 \times 10^{-5}\ C$

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

$q =\dfrac{mg}{E}$

$q =\dfrac{0.00141 \times 9.81}{670}$

$q = 2.067 \times 10^{-5}\ C$

Charge of the particle is equal to $q = 2.067 \times 10^{-5}\ C$

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3 years ago

Modern scientists say that electrons are found in a ...

bulgar [2K]

I think it might be a or d i hope i have helped :)

8 0

3 years ago

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