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Nuetrik [128]
3 years ago
14

Which of the following is an example of distance equaling displacement?

Physics
1 answer:
AleksandrR [38]3 years ago
3 0

Answer:

D

Explanation:

The student had displaced their in the class when she left. The phone is what's displaced and student leaving equals distance.

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Plz help, and show work
pentagon [3]

Answer:

1. 2.67 s

2. 0.1 m/s²

Explanation:

1. Determination of the time taken for the penguin to fall.

Height (h) of cliff = 35 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

35 = ½ × 9.8 × t²

35 = 4.9 × t²

Divide both side by 4.9

t² = 35 / 4.9

Take the square root of both side

t = √(35 / 4.9)

t = 2.67 s

Thus, it will take 2.67 s for the penguin to fall onto the head of a napping polar bear.

2. Determination of the acceleration of the penguin.

Initial velocity (u) = 0 m/s.

Final velocity (v) = 2 m/s.

Time (t) = 20 s

Acceleration (a) =?

a = (v – u)/t

a = (2 – 0)/ 20

a = 2 / 20

a = 0.1 m/s²

Thus, the acceleration of the penguin is 0.1 m/s²

8 0
3 years ago
A student is preparing to bake a cake at home and places several ingredients on the countertop to use. First he preheats the ove
Evgen [1.6K]

Answer:

baking the cake batter

Explanation:

Baking the cake batter will indicate that chemical change has occurred here. What is a chemical change?

  • A chemical change is one in which a new kind of matter is formed.
  • It is usually accompanied by energy either evolution or absorption of energy in form of heat or light or both.
  • The process is irreversible.
  • When the batter bakes, a new substance different from the cake mix is obtainable.
  • We cannot get back the ingredient from this baked cake. It is impossible.
  • This is good indicator of chemical change.
7 0
3 years ago
What happens to the kinetic energy of a body when: a) the mass of the body is doubled at constant velocity? b) the velocity of t
blagie [28]
Using the formula KE=1/2mv^2

a: The kinetic energy doubles.
b: The kinetic energy quadruples.
c: The kinetic energy is cut in half.
Hopefully it’s clear how the formula can show you this.
3 0
3 years ago
An astronaut having mass 320 kg with equipment included is attempting an untethered space walk. The astronaut is initially at re
ExtremeBDS [4]
This can be solved using momentum balance, since momentum is conserved, the momentum at point 1 is equal to the momentum of point 2. momentum = mass x velocity
m1v1 = m2v2
(0.03kg x 900 m/s ) = 320(v2)
v2 = 27 / 320
v2 = 0.084 m/s is the speed of the astronaut
7 0
3 years ago
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
Inessa05 [86]

Answer:

A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel

20miles / 5sec = 4miles /sec would be the average speed for the last 20 m

Explanation:

The answer is 4 m/s.

In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).

The relation of speed (v), distance (d), and time (t) can be expressed as:

v = d/t

We need to calculate the speed of the second 5 seconds of the travel:

d = 20 m (total 30 meters - first 10 meters)

t = 5 s (time from t = 5 seconds to t = 10 seconds)

Thus:

v = 20m / 5s = 4 m/s

PLEASE GIVE BRAINIEST!! HOPE THIS HELPS

5 0
3 years ago
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