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3 years ago

each block weighs 7 pounds and the wagon can only carry 77 pounds at a time how many blocks can you carry in the wagon at a time

Mathematics

1 answer:

Agata [3.3K]3 years ago

4 0

11 blocks can be carried at a time

Hope this helps :)

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A sample of size =n72 is drawn from a population whose standard deviation is =σ25. Part 1 of 2 (a) Find the margin of error for

kherson [118]

Answer:

a) margin of error ME = 5.77

b) Margin of error becomes smaller

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

x+/-ME

Where margin of error ME = zr/√n

Given that;

Mean = x

Standard deviation r = 25

Number of samples n = 72

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

ME = 1.96(25/√72)

ME = 1.96(2.946278254943)

ME = 5.774705379690

ME = 5.77

For n = 89

ME = 1.96(25/√89)

ME = 1.96(2.649994700015)

ME = 5.193989612031

ME = 5.19

5.19 is smaller than 5.77 in a) above. So,

Margin of error becomes smaller

6 0

2 years ago

Consider the quadratic equation x squared = 4x - 5. how many solutions does the equation have?

snow_lady [41]

Answer:

The quadratic equation has two complex solutions

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}=4x-5$

Equate to cero

$x^{2}-4x+5=0$

$a=1\\b=-4\\c=5$

substitute in the formula

$x=\frac{4(+/-)\sqrt{-4^{2}-4(1)(5)}} {2(1)}$

$x=\frac{4(+/-)\sqrt{16-20}} {2}$

$x=\frac{4(+/-)\sqrt{-4}} {2}$

Remember that

$i^{2}=-1$

$x=\frac{4(+/-)2i} {2}$

$x=2(+/-)i$

therefore

The quadratic equation has two complex solutions

5 0

3 years ago

Express log2 64-log2 4 as a simple logarithm

Triss [41]

<span>Express log(2)64-log(2)4 as a single logarithm.
Simplify as possible.
Solution:

= log(2)[64/4]
= log(2)[16]
= 4
</span>

4 0

3 years ago

Find the empirical formula of the compound containing 2.4 gram of carbon, 6.4 gram of oxygen and 0.2 gram of hydrogen

Usimov [2.4K]

Answer:

Empirical formula= COOH

Step-by-step explanation:

Molecular mass of the elements

Carbon= 12

Oxygen= 16

Hydrogen= 1

We divide the elements each with their molecular formula

Carbon= 2.4/12

Carbon= 0.2

Oxygen= 6.4/16

Oxygen= 0.4

Hydrogen= 0.2/1

Hydrogen= 0.2

Now we divide with the smallest result which is 0.2

Carbon= 0.2/0.2

Carbon = 1

Oxygen= 0.4/0.2

Oxygen= 2

Hydrogen= 0.2/0.2

Hydrogen= 1

So we have

Carbon 1, oxygen 2, hydrogen 1

Empirical formula= COOH

4 0

3 years ago

What is 873 divided by 35?!!

EastWind [94]

873 divided by 35= 24 33/35

8 0

3 years ago