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lisov135 [29]
3 years ago
14

The image shows a diagram. which descriptions best fit the labels

Physics
2 answers:
bulgar [2K]3 years ago
7 0
Where is the diagram
ozzi3 years ago
7 0
Where’s the diagram??
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a block is pushed up a frictionless 40 incline. if the initial velocity after the push is 5.00 m/s. how far along the incline do
Lana71 [14]

Answer:

d=1.982m, t=1.019s

Explanation:

There are different approaches we can take to solve this problem. You could either solve this by using conservation of energy or by taking a kinematic approach. I'll solve this by using kinematics. So, the very first thing we need to do in order to solve this is do a drawing of the situation so we can analyze it better. (See attached picture).

So, since we are talking about an inclined plane, we can see that the force of gravity is being split into an x and y components if we incline the axis of coordinates. Taking this into account we can see that:

\sum F_{x}=ma_{x}

Since there is no friction in our system, then the only force acting upon the box is the force of gravity, or weight. Since we are taking the upwards direction as the positive direction of movement, we can say that the force of gravity is excerting a negative influence on our box, so this acceleration will be negative, so our sum of forces will now look like this:

-mg sin(40^{o})=ma

we can cancel the masses out so we can see that:

a=-g sin(40°)

a=-9.81m/s^{2} sin(40^{o})

We have now enough information to solve our problem.

we can take the following equation to find the distance the block travels up the incline:

x=\frac{V_{f}^{2}-V_{0}^{2}}{2a}

we know the final velocity must be zero, so we can use the provided data to solve our formula:

x=\frac{(0)^{2}-(5m/s)^{2}}{2(-9.81m/s^{2})sin 40^{o}}

which yields:

x=1.982m

In order to find the time it takes for the block to return to its original position we can use the following formula:

x=V_{0}t+\frac{1}{2}at^{2}

since x=0 is the starting point we can use that to solve our equation:

0=5t+\frac{1}{2}(-9.81sin 40^{o})t^{2}

which simplifies to:

0=5t-4.905t^{2}

which can now be solved for t

t(5-4.905t)=0

t=0                and          5-4.905t=0

t=0                 and         t=\frac{5}{4.905}=1.019

so the time it takes the block to return to its original position is

t= 1.019s

6 0
3 years ago
A force F= (6.70 N)i + (5.60 N)j + (6.60 N)k act on a 9.80 kg mobile object that moves from an initial position of di = (9.10 m)
Mandarinka [93]

Answer:

W = 0.11J

P = 0.0186W

Explanation:

Please see attachment below.

4 0
3 years ago
Predict how heat would flow if beaker A is moved so that it's touching beaker B A. Heat would flow from beaker B to beaker A. B.
jek_recluse [69]
Zeroth Law of Thermodynamics, which in turn will mean the heat will transfer between both of them up to the point where they are in thermodynamic equilibrium. So the answer is C.
6 0
3 years ago
A 1000 kg train car traveling at 12 m/s on a level track has 400 kg of sand dumped, vertically, into it. What is the final speed
crimeas [40]

Answer:

The final speed of the train car is 8.57 m/s.

Explanation:

Given that,

Mass of train car = 1000 kg

Mass of sand = 400 kg

Speed of train car = 12 m/s

We need to calculate the final speed of the train car after the sand is dumped

Using conservation of momentum

m_{1}u_{1}=(m_{1}+m_{2})v...(I)

Put the value in the equation (I)

1000\times12=(1000+400)v

v=\dfrac{1000\times12}{1400}

v=8.57\ m/s

Hence, The final speed of the train car is 8.57 m/s.

5 0
3 years ago
Write balanced nuclear equation for the decay of strontium 94 into yttrium
Dmitriy789 [7]

The nuclear decay equation is _{38}^{94}Sr \rightarrow _{39}^{94}Y + e^- + \overline{\nu}

Explanation:

First of  all, we look at the periodic table to see what is the atomic number of the two elements involved.

We notice that:

  • The atomic number of strontium is 38
  • The atomic number of yttrium is 39

This means that in the decay, a neutron from the nucleus of strontium transforms into a proton (because the atomic number, which is the number of protons, increases by 1 unit).

Therefore, this means that the decay involved is a beta-minus decay, in which a neutron converts into a proton emitting an electron (to conserve the charge) alongside an anti-neutrino.

Therefore, the balanced nuclear decay equation is:

_{38}^{94}Sr \rightarrow _{39}^{94}Y + e^- + \overline{\nu}

where the mass number (94) does not change, since the number of nucleons (protons+neutrons) remains the same.

Learn more about radioactive decay:

brainly.com/question/4207569

brainly.com/question/1695370

#LearnwithBrainly

8 0
4 years ago
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