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rodikova [14]
3 years ago
15

You wish to cook some pasta and so take some water and heat it on a stove. If you use 2000 grams of water with an initial temper

ature of zero degrees C, how much energy would you need to add to raise the temperature to 100° C is all of the stove energy went into heating the water?
Physics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

the stove energy went into heating water is 837.2 kJ.

Explanation:

given,

mass of water = 2000 grams

initial temperature = 0° C

Final temperature = 100° C

specific heat of water (c) = 4.186 joule/gram

energy = m c Δ T                            

            = 2000 × 4.186 × (100° - 0°)

            = 837200 J                          

             = 837.2 kJ            

hence, the stove energy went into heating water is 837.2 kJ.

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A sixth grader moves down the hall at 1.2 m/s. When he sees a bunch of eighth graders coming, he
balandron [24]

Answer:

0.75m/s^2

Explanation:

3.6-1.2=2.4 m/s (Change in velocity)

2.4/3.2=0.75 m/s/s or m/s^2

5 0
3 years ago
phase, color, and ductility are all examples of what type of property? chemical changeable physical external
svet-max [94.6K]
<span>Phase, color, and ductility are all examples of physical external properties</span>
3 0
3 years ago
A bullet of mass 120g is fired horizontally into a fixed wooden block with a speed of 20m\s. The bullet is brought to rest in a
prohojiy [21]

Answer:

1) F = 24 N

2) Distance = 1 m

Explanation:

We are given;

Mass; m = 120 g = 0.12 kg

Initial velocity; u = 20 m/s

Final velocity; v = 0 m/s since it came to rest.

Time; t = 0.1 s

We can calculate acceleration from Newton's first equation of motion;

a = (v - u)/t

a = (0 - 20)/0.1

a = -200 m/s²

1) magnitude of the resistance will be;

F = ma

F = 0.12 × (-200)

F = -24 N

Since, we are dealing with the magnitude, we will take the absolute value. Thus, F = 24 N

2) To find the distance moved by the bullet, we know that;

Distance = Average speed × time

Thus;

Distance = ((v + u)/2) × t

Distance = ((0 + 20)/2) × 0.1

Distance = 1 m

4 0
3 years ago
A 40-kg rock is dropped from an elevation of 10 m. What is the velocity of the rock when it is 5-m from the ground?
ivolga24 [154]

Answer:

Explanation:

Given

mass of rock m=40\ kg

Elevation of Rock h=10\ m

Distance traveled by rock with time

h=ut+\frac{1}{2}at^2

where, u=initial velocity

t=time

a=acceleration

here initial velocity is zero

when rock is 5 m from ground then it has traveled a distance of 5 m from top because total height is 10 m

5=0\times t+\frac{1}{2}(9.8)(t^2)

t^2=\frac{10}{9.8}

t=1.004\approx 1\ s

velocity at this time

v=u+at

v=0+9.8\times 1.004

v=9.83\ m/s

6 0
3 years ago
Distance v. Time
Allushta [10]

Answer:

4

(m)

2 ( s )

Explanation:

ok...........

3 0
4 years ago
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