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Stella [2.4K]
3 years ago
7

Using the periodic table, determine the ion charges of the following families of elements if valence electrons were removed or a

dded to reach the octet. Group I = Group VI = Group III =
Chemistry
2 answers:
kogti [31]3 years ago
6 0

Group I=1+

Group VI=-2

Group III=3+

igomit [66]3 years ago
4 0

<u>Answer:</u> The ion charge formed by Group I will be +1, by Group VI will be -2 and by Group III will be +3.

<u>Explanation:</u>

Ions are formed when electrons are lost or gained by an atom. When an atom looses electrons, it forms a positive ion known as cations and when an atom gains electrons, it forms a negative ion known as anions.

The electronic configuration of the elements present in

  • <u>Group I:</u> ns^1 where n is the number of period

This configuration will loose 1 electron and thus will form an ion of +1.

  • <u>Group VI:</u> ns^2np^4 where n is the number of period

This configuration will gain 2 electrons and thus will form an ion of -2.

  • <u>Group III:</u> ns^2np^1 where n is the number of period

This configuration will loose 3 electrons and thus will form an ion of +3.

Hence, the ion charge formed by Group I will be +1, by Group VI will be -2 and by Group III will be +3.

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Answer:

NH4NO3

Explanation:

I hope this helps you:)

5 0
3 years ago
Consider the reaction 2CO(g) + O2(g)2CO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr
Marizza181 [45]

<u>Answer:</u> The value of \Delta S^o for the surrounding when given amount of CO is reacted is 432.52 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

2CO(g)+O_2(g)\rightarrow 2CO_2(g)

The equation for the entropy change of the above reaction is:  

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(CO_2(g))})]-[(1\times \Delta S^o_{(O_2(g))})+(2\times \Delta S^o_{(CO(g))})]

We are given:

\Delta S^o_{(CO_2(g))}=213.74J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(CO)}=197.674J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (213.74))]-[(1\times (205.14))+(2\times (197.674))]\\\\\Delta S^o_{rxn}=-173.008J/K

Entropy change of the surrounding = - (Entropy change of the system) = -(-173.008) J/K = 173.008 J/K

We are given:

Moles of CO gas reacted = 2.25 moles

By Stoichiometry of the reaction:

When 2 moles of CO is reacted, the entropy change of the surrounding will be 173.008 J/K

So, when 2.25 moles of CO is reacted, the entropy change of the surrounding will be = \frac{173.008}{1}\times 2.25=432.52J/K

Hence, the value of \Delta S^o for the surrounding when given amount of CO is reacted is 432.52 J/K

3 0
3 years ago
I need help so please help me
Kay [80]

Answer:b

Explanation:

I honestly don’t know if this I right but that would be my guess

3 0
3 years ago
Rust forming on a piece of iron is an example of which of the following? *
kvasek [131]
Rust is an iron oxide and formed by the reaction of iron and oxygen in the presence of moisture. So the answer would be C
8 0
3 years ago
What is the oxidation number of iron in FeO?
kiruha [24]

Answer:

+2

Explanation:

3 0
3 years ago
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