3 years ago

What is the wave speed of a wave that has a frequency of 250 Hz and a wavelength of 0.35 m?

Physics

1 answer:

azamat3 years ago

6 0

Answer:

87.5 m/s

Explanation:

The speed of a wave is given by

$v=\lambda f$

where

v is the wave speed

$\lambda$ is the wavelength

f is the frequency

In this problem, we have

$f=250 Hz$ is the frequency

$\lambda=0.35 m$ is the wavelength

Substituting into the equation, we find

$v=(0.35 m)(250 Hz)=87.5 m/s$

You might be interested in

A 60-watt light bulb has a voltage of 120 volts applied across it and a current of 0.5 amperes flows through the bulb. What is t

Naddik [55]

Answer: 240ohms

Explanation: P=IV

P=60watts

I=0.5A

V=120volts

From ohms law

V=IR

R=V/I

R=120/0.5

R= 240ohms

7 0

3 years ago

What is a 7 letter word that describes the relationship between frequency and period?

adoni [48]

Present. NOT SURE IF THIS IS EVEN RIGHT!! I JUST GUESSED AND THOUGHT

3 0

3 years ago

Covalent bonds form when electrons are

NeX [460]

It would be A) shared

8 0

3 years ago

Read 2 more answers

A sinusoidal, transverse wave that propagates in the positive x-direction can be described with the wave function y of xt is equ

myrzilka [38]

Answer:

$\omega =\frac{2 \pi }{T}$ rad/s

Explanation:

The wave function is:

$y(xt) = Acos(kx- \omega t)$

where :

k = wave number

x = position of a point on the wave

$\omega$ = angular frequency

t = time

What is another way to express the angular frequency (omega)

Angular frequency (omega) can be express as :

$\omega =\frac{2 \pi }{T}$ rad/s ( i.e one repetition that it takes to repeats itself)

4 0

3 years ago

In trampoline competitions, a good jump is one that lasts about 1.8 seconds. (A) How high can an athlete who stays in the air 1.

KonstantinChe [14]

Answer:

3.97305 m

Explanation:

a = Acceleration due to gravity = 9.81 m/s²

If a jump lasts for 1.8 seconds this means that from the moment when the person leaves the ground till the person touches the ground again it takes 1.8 seconds. So, maximum height reached will be at half the time of the jump i.e., 0.9 seconds.

u = Initial velocity = 0

Equation of motion

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=0t+\frac{1}{2}9.81\times 0.9^2\\\Rightarrow s=3.97305\ m$

So, height of the jump is 3.97305 m.

4 0

3 years ago