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Fiesta28 [93]
4 years ago
14

What two variables are multiplied together to calculate mass?

Physics
1 answer:
Aleksandr [31]4 years ago
8 0

Volume x Density = Mass

or

Weight / Gravity = Mass

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A satellite is launched to orbit the Earth at an altitude of 3.25 107 m for use in the Global Positioning System (GPS). Take the
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Answer:Orbital period =21.22hrs

Explanation:

given that

mass of earth M = 5.97 x 10^24 kg

radius of a satellite's orbit, R=  earth's radius + height of the satellite

6.38X 10^6 +  3.25 X10^7 m =3.89 X 10^7m

Speed of satellite, v= \sqrt GM/R

where G = 6.673 x 10-11 N m2/kg2

V= \sqrt (6.673x10^-11 x 5.97x10^ 24)/(3.89 X 10^ 7m)

V =10,241082.2

v= 3,200.2m/s

a) Orbital period

\sqrt GM/R = \frac{2\pi r}{T}

V= \frac{2\pi r}{T}

T= 2 \pi r/ V

= 2 X 3.142 X 3.89 X 10^7m/ 3,200.2m/s

=76,385.1 s

60 sec= 1min

60mins = 1hr

76,385.1s =hr

76,385.1/3600=21.22hrs

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The interaction between two optical and perceptual phenomena makes moving pictures possible. the persistence of vision provides
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Plzzzz urgent <br><br><br>solve this​
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Answer:

\large{ \tt{☄ \: EXPLANATION}} :

  • Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0

  • Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]

  • Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .

\large{ \tt{♨ \:LET'S \: START}} :

  • Acceleration is defined as the rate of change of velocity. We know :

\large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) =  \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}}

- Plug the values & then simplify !

\large{ \bf{↬a =  \frac{60 - 0}{300}  =  \frac{60}{300} =  \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}

  • The acceleration of the jeep is 0.2 m/s²

\large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} :

\boxed{ \large{ \bf{✾ \: s =  \frac{u + v}{2}  \times t}}}

- Plug the values & then simplify !

\large{ \bf{↦s =  \frac{0 + 60}{2}  \times 300 =  \boxed{ \bold{ \bf{9000 \: m}}}}}

  • The distance covered by the jeep is 9000 m .

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7 0
3 years ago
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