Complete question:
The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.
Answer:
The exit velocity is 629.41 m/s
Explanation:
Given;
initial temperature, T₁ = 1200K
initial pressure, P₁ = 150 kPa
final pressure, P₂ = 80 kPa
specific heat at 300 K, Cp = 1004 J/kgK
k = 1.4
Calculate final temperature;
k = 1.4
Work done is given as;
inlet velocity is negligible;
Therefore, the exit velocity is 629.41 m/s
Classically, gravitational attraction is due to the masses of objects. It is inversely proportional to the square of the distances between the objects.
Magnetic attraction is due to the magnetism in objects which is due to uncompensated electron spins in certain atoms. The force due to magnetism less easy to put into one equation than gravity since magnetic fields can have different shapes, but the simplest one (the dipolar field) is inversely proportional to the cube of the distance between the magnetic dipoles.
Answer:
15.3 m/s
Explanation:
Radius of orbit= 6400+6300 = 12700 km
Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m
Now,
Speed= Distance / Time
= 79796.45*10^3/(24*60*3600)
= 15.3 m/s
Answer:accelaration will decrease because forse is inversly proportional to mass.
Explanation:
Answer:
Option B, two walls and the floor
Explanation:
The distance should be measured from the point where at least the three axed meet.
Two walls and the floor are equivalent to three axes.
Vertical wall 1 = Y Axis
Horizontal wall2 = X Axis
Floor = Z Axis
Thus, the distance should be measured from the point where two walls and one floor meet.
Option , B is correct
