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vesna_86 [32]
3 years ago
11

Which of the following laws relates emf, potential, current, and resistance in a circuit? Ohm’s Law Newton’s Law of Gravity Coul

omb’s Law Conservation of Charge
Physics
2 answers:
lisabon 2012 [21]3 years ago
3 0
I think it’s Ohm’s Law.
joja [24]3 years ago
3 0

Answer:

Ohm's law

Explanation:

As per ohm's law we know that the potential difference across the resistance is applied then the current flows through is given by

i = \frac{V}{R}

here we know that

V = EMF or potential difference across the resistance

R = Resistance

i = electric current

So ohm's law relates the potential difference across the resistance and current flow through the resistance with the resistance of the wire

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A cricket player catches the ball leaning towards to the ground,why?​
Vadim26 [7]

Answer:

Explanation:

As it’s difficult to catch it from up.

Gravitational force will pull us when we jump.

If gravity was not there, he could catch the ball. But he will float in the sky after that.

That’s the answer

3 0
3 years ago
A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
Evgen [1.6K]

Answer:

\dfrac{d\theta}{dt}=0.038\ rad/s

Explanation:

Given that

\dfrac{dx}{dt}= -1\ m/s

From the diagram

tan\theta=\dfrac{21}{x}

By differentiating with time t

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

When x= 10 m

tan\theta=\dfrac{21}{10}

θ = 64.53°

Now by putting the value in equation

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)

\dfrac{d\theta}{dt}=0.038\ rad/s

Therefore rate of change in the angle is 0.038\ rad/s

8 0
3 years ago
How many kj of heat are needed to completely melt 144 g of titanium metal, given that the metal is at its melting point? the hea
Elina [12.6K]

Given, mass of titanium metal = 144 g

Heat of fusion of titanium metal= 18.7 J/g

Heat of fusion is the amount of heat energy needed to change the state of one gram of a substance from solid to liquid or vice-versa.

Thus, 18.7 J of heat is needed to melt one gram of titanium metal.

Therefore, heat needed to melt 144 g of titanium metal = 18.7×144

= 2692.8 J

8 0
3 years ago
An airplane is flying through a thundercloud at a height of 2000 m (This is a very dangerous thing to do because of updrafts, tu
Doss [256]

Answer:

400000\ \text{N/C}

Explanation:

q_1 = Charge at 3000 m = 40 C

q_2 = Charge at 1000 m = -40 C

r_1 = 3000 m

r_2 = 1000 m

k = Coulomb constant = 9\times10^9\ \text{Nm}^2/\text{C}^2

Electric field due to the charge at 3000 m

E_1=\dfrac{k|q_1|}{r_1^2}\\\Rightarrow E_1=\dfrac{9\times 10^9\times 40}{3000^2}\\\Rightarrow E_1=40000\ \text{N/C}

Electric field due to the charge at 1000 m

E_2=\dfrac{k|q_2|}{r_2^2}\\\Rightarrow E_2=\dfrac{9\times 10^9\times 40}{1000^2}\\\Rightarrow E_2=360000\ \text{N/C}

Electric field at the aircraft is E_1+E_2=40000+360000=400000\ \text{N/C}.

7 0
3 years ago
A parallel-plate capacitor consists of plates of area 1.5 x 10^-4 m^2 separated by 2.0 mm The capacitor is connected to a 12-V b
Katen [24]

Answer:

4.78 x 10^-11 J

Explanation:

A = 1.5 x 10^-4 m^2

d = 2 mm = 2 x 10^-3 m

V = 12 V

Let C be the capacitance of the capacitor

C = ε0 A / d

C = (8.854 x 10^-12 x 1.5 x 10^-4) / (2 x 10^-3)

C = 6.64 x 10^-13 F

Energy stored, U = 1/2 CV^2

U = 0.5 x 6.64 x 10^-13 x 12 x 12

U = 4.78 x 10^-11 J

4 0
3 years ago
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