The all purpose one will work or you could use type C I believe.
Answer:
Explanation:
- a) Given C [ cal pro fat calc sod]
[140 27 3 13 64]
- P = [cal pro fat calc sod]
[180 4 11 24 662]
- B = [cal pro fat calc sod]
[50 5 1 82 20]
To find C+2P+3B = [140 27 3 13 64] + 2[180 4 11 24 662] + 3[50 5 1 82 20]
= [650 54 28 307 1448]
The entries represent skinless chicken breast , One-half cup of potato salad and One broccoli spear.
Answer:
The electrical work for the process is 256.54 Btu.
Explanation:
From the ideal gas equation:
n = PV/RT
n is the number of moles of air in the tank
P is initial pressure of air = 50 lbf/in^2 = 50 lbf/in^2 × 4.4482 N/1 lbf × (1 in/0.0254m)^2 = 344736.2 N/m^2
V is volume of the tank = 40 ft^3 = 40 ft^3 × (1 m/3.2808 ft)^3 = 1.133 m^3
T is initial temperature of air = 120 °F = (120-32)/1.8 + 273 = 321.9 K
R is gas constant = 8.314 J/mol.k
n = 344736.2×1.133/8.314×321.9 = 145.94 mol
The thermodynamic process is an isothermal process because the temperature is kept constant.
W = nRTln(P1/P2) = 145.94×8.314×321.9×ln(50/25) = 145.94×8.314×321.9×0.693 = 270669 J = 270669 J × 1 Btu/1055.06 J = 256.54 Btu
Answer:
dy/dx = (1 − 2x + 8y) / (4 + 3x − 12y)
Explanation:
d/dx (x − 4y) = d/dx (e^(2x + 3y − 1))
1 − 4 dy/dx = e^(2x + 3y − 1) (2 + 3 dy/dx)
Since x − 4y = e^(2x + 3y − 1):
1 − 4 dy/dx = (x − 4y) (2 + 3 dy/dx)
1 − 4 dy/dx = 2 (x − 4y) + 3 (x − 4y) dy/dx
1 − 4 dy/dx = 2x − 8y + (3x − 12y) dy/dx
1 − 2x + 8y = (4 + 3x − 12y) dy/dx
dy/dx = (1 − 2x + 8y) / (4 + 3x − 12y)
