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IrinaVladis [17]
3 years ago
6

Which term defines the amount of mechanical work an engine can do per unit of heat energy it uses?

Engineering
1 answer:
skad [1K]3 years ago
7 0

Answer:

d

Explanation:

is the because that's the amount of work in making machine can do producing heat

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An inventor claims to have devised a cyclical power engine that operates with a fuel whose temperature is 750 °C and radiates wa
Phantasy [73]

Answer:

Yes

Explanation:

Given Data

Temprature of source=750°c=1023k

Temprature of sink =0°c=273k

Work produced=3.3KW

Heat Rejected=4.4KW

Efficiency of heat engine(η)=\frac{Work produced}{Heat supplied}

and

Heat Supplied {\left (Q_s\right)}=Work Produced(W)+Heat rejected\left ( Q_r \right )

{Q_s}=3.3+4.4=7.7KW

η=\frac{3.3}{7.7}

η=42.85%

Also the maximum efficiency of a heat engine operating between two different Tempratures i.e. Source & Sink

η=1-\frac{T_ {sink}}{T_ {source}}

η=1-\frac{273}{1023}

η=73.31%

Therefore our Engine Efficiency is less than the maximum efficiency hence the given claim is valid.

5 0
3 years ago
Is 4/16 equal in measurement to 1/4
Alja [10]

Answer:yes

Explanation:

5 0
3 years ago
Read 2 more answers
Weight and mass of an object are the same by
dangina [55]

Answer:

Explanation:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass. Mass is the measure of the amount of matter in a body. ... Weight usually is denoted by W. Weight is mass multiplied by the acceleration of gravity (g).

6 0
3 years ago
Which of the following shot pellets has the smallest diameter?
vitfil [10]
I believe i got this correct when i had an assignment with this question. It should be 7 1/2. B!
5 0
3 years ago
Considere uma estufa usada em um laboratório qualquer. A câmara tem formado de um cubo perfeito com lado igual a 75 cm, desse mo
levacccp [35]

Responder:

0.0328m

Explicación:

La tasa de transferencia de calor se expresa como se muestra

Q / t = kA∆T / d

Q / t es la tasa de transferencia de calor o la energía consumida

k es la conductividad térmica

A es el área de superficie del cubo

∆T es el cambio de temperatura

d es el grosor Dado que

Q = Potencia × tiempo Potencia = Q / t = 900W

K = 0,025 W / m. K

Área de superficie del cubo A = 6a²

A = 6 (0.75) ²

A = 3.375m²

d es el grosor =?

∆T = T2-T1 ∆T = 105 ° C-28 ° C

∆T = 77 ° C ∆T = 77 + 273 = 350 Kelvin

Al sustituir los valores en la fórmula para obtener el grosor 'd' que tenemos;

900 = 0.025 × 3.375 (350) / día Multiplicación cruzada que tenemos; 900d = 29.53125

d = 29.53125 / 900

d = 0.0328m

El espesor es de 0.0328 m

5 0
3 years ago
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