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3 years ago

Two masses sit at the top of two frictionless inclined planes that have different angles. Which mass gets to the bottom first?

Physics

2 answers:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

Explanation:

Let the two inclined planes having angle of inclinations α and β.

The acceleration along the inclined plane acting on the body is gSinα and gSinβ.

If α > β

So, g Sinα > g Sinβ

So, more the inclination of the plane more be the acceleration of body and hence the time taken is less.

So, the body kept on the inclined whose inclination is more reaches at the bottom first.

yulyashka [42]3 years ago

3 0

Answer:

both mass take equal time to reach at bottom

Explanation:

As both masses M 1 and M 2 are situated at same height so that the potential energy at top is transformed to kinetic energy at the bottom by applying principle of energy conservation.

PE = KE

Mgh = (1/2)(M)(V^2)

V^2 = 2gh

V = (2gh)^(1/2)

So velocity is independent of mass

For M1

(M_1)(g)(h) = (1/2)(M1)(V^2)

V^2 = 2gh

V = (2gh)^(1/2)

For M2

(M_2)(g)(h) = (1/2)(M2)(V^2)

V^2 = 2gh

V = (2gh)^(1/2)

therefoer speed at bottom too are independent of mass

So we can say both speed are independent of therir respective mass

hence both take equal time to reach at bottom

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3 years ago

2. A 56N force is exerted on an 8kg object. What is the object's acceleration?

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acceleration = 7 m/s²

Explanation:

To determine the object's acceleration we use the following formula:

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2 years ago

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3 years ago

A force of 10. N toward the right is exerted on a wooden crate initially moving to the right on a horizontal wooden floor. the c

Artyom0805 [142]

1) 5 N

The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:

$F_f = \mu_k mg$

where

$\mu_k=0.2$ is the coefficient of friction between the crate (made of wood) and the floor (made of wood). The coefficient of kinetic friction between wood and wood is about 0.2.

$mg=25 N$ is the weight of the crate

Substituting the numbers into the formula, we find

$F_f=(0.2)(25 N)=5 N$

2) 5 N

There are two forces acting on the crate along the horizontal direction:

- The force that pushes the crate toward the right, of magnitude $F=10 N$

- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude $F_f = 5 N$

Since the two forces are in opposite directions, the net force is given by their difference:

$F_{net}=F-F_f = 10 N-5 N=5 N$

3) Yes

The crate is accelerating. In fact, according to Second Newton's Law:

$F_{net}=ma$ (1)

where Fnet is the net force on the crate, m is its mass, a is its acceleration. We can immediately see that since Fnet is not zero, the acceleration is also non-zero, so the crate is accelerating.

We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:

$m=\frac{Weight}{g}=\frac{25 N}{9.8 m/s^2}=2.55 kg$

And by using (1) we find

$a=\frac{F_{net}}{m}=\frac{5 N}{2.55 kg}=1.96 m/s^2$

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3 years ago