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FrozenT [24]
3 years ago
15

A car is driving down the highway at a 50 m/s. Suddenly, the driver sees an accident and slams on his breaks, coming to a comple

te stop in 10 seconds. How far did the car travel before coming to a stop?
Physics
1 answer:
vlada-n [284]3 years ago
4 0

Given parameters:

Speed of the car = 50m/s

Time  = 10s

Unknown:

Distance traveled before the car stopped = ?

We need to establish speed - time - distance relationship.

Speed is the rate of change of distance with time. It is a scalar quantity .

Mathematically;

            Speed  = \frac{distance}{time}

    Distance  = speed x time

Input the parameters and solve;

    Distance  = 50 x 10  = 500m

The car traveled 500m before it stopped.

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Theories result from several repeated experiments.

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8 0
3 years ago
A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of 70.0 from the horizontal w
professor190 [17]

Answer: 211.059 m

Explanation:

We have the following data:

\theta=70\° The angle at which the ball leaves the bat

V_{o}=55 m/s The initial velocity of the ball

g=-9.8 m/s^{2} The acceleration due gravity

We need to find how far (horizontally) the ball travels in the air: x

Firstly we need to know this velocity has two components:

<u>Horizontally:</u>

V_{ox}=V_{o}cos \theta (1)

V_{ox}=55 m/s cos(70\°)=18.811 m/s (2)

<u>Vertically:</u>

V_{oy}=V_{o}sin \theta (3)

V_{oy}=55 m/s sin(70\°)=51.683 m/s (4)

On the other hand, when we talk about parabolic movement (as in this situation) the ball reaches its maximum height just in the middle of this parabola, when V=0 and the time t is half the time it takes the complete parabolic path.

So, if we use the following equation, we will find t:

V=V_{o}+gt=0 (5)

Isolating t:

t=\frac{-V_{o}}{g} (6)

t=\frac{-55 m/s}{-9.8 m/s^{2}} (7)

t=5.61 s (8)

Now that we have the time it takes to the ball to travel half of is path, we can find the total time T it takes the complete parabolic path, which is twice t:

T=2t=2(5.61 s)=11.22 s (9)

With this result in mind, we can finally calculate how far the ball travels in the air:

x=V_{ox}T (10)

Substituting (2) and (9) in (10):

x=(18.811 m/s)(11.22 s) (11)

Finally:

x=211.059 m

8 0
3 years ago
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