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Darya [45]
3 years ago
7

A 120V Microwave uses 8A of current. It runs for 15 hours over the course of a month. If electrical energy costs $0.11/KWh, what

does it cost to run the microwave for the month
Physics
1 answer:
Reika [66]3 years ago
7 0

Answer:

Monthly energy cost = $47.52

Explanation:

Given the following data;

Voltage = 120 Volts

Current = 8 Ampere

Time = 15 hours

Energy cost = $0.11/KWh

To find the energy cost for a month;

First of all, we would determine the power rating of the microwave oven.

Power = current * voltage

Power = 8 * 120

Power = 960 Watts

Next, we find the amount of energy consumed;

Energy = power * time

Energy = 960 * 15

Energy = 14400 Watt-hour

To kilowatt per hour, we have;

Energy = 14400/1000 = 14.4 KWh

Now, we determine the monthly energy cost;

Daily energy cost = Energy consumption * cost

Daily energy cost = 14.4 * 0.11

Daily energy cost = $1.584

Therefore, monthly energy cost = 1.584 * 30

Monthly energy cost = $47.52

Or

Monthly energy cost = 14.4 * 0.11 * 30

Monthly energy cost = $47.52

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Answer:

When equal and opposite forces meet each other, it results in motion and they would repel away from each other, causing the asteroid to be sent away from the earth.

Explanation:

Newton's Third Law states that every action has an equal and opposite reaction.

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3 years ago
1. The basic building block of matter are atoms. Every atom is basically a tiny sphere. Every atom is composed of 2 regions, the
Bogdan [553]

The answers would be:

1. Electron cloud

2. Electrons, Electrons, Electrons

3. Nucleus, nucleus

4. Protons, protons

5. Neutrons, Neutrons

6. Direct, direct.

7. Inverse, inverse

8. No relationship, no relationship

9. Experimental control

10. Controlled variables

Here is more about the question:

An atom has 3 subatomic particles:

Proton: positively charged particles

Electron: Negatively charged particles

Neutrons: Neutrally charged particles

The nucleus is made up of the protons and neutrons, while the electrons are found outside, within the electron cloud.

Electrons are very important in bonding. It is also heavily involved in electricity. Electricity is the flow of electrons through a conductor.

Relationships in a graph:

For direct relationships, you just need to remember, when one goes up, the other one goes up too.

Inverse relationships on the other hand, when one goes up the other goes down.

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6 0
3 years ago
Me ajudem, Por favor!!!!!!
zzz [600]

Answer:

a)  a=4\,\frac{m}{s^2}

b)  V(t)=4\,t\,+3

c)  V(1)=7 \,\frac{m}{s} \\

d)  Displacement = 22 m

e)  Average speed = 11 m/s

Explanation:

a)

Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:

slope= \frac{15=3}{3-0} =4\,\frac{m}{s^2}

Therefore,  acceleration is a=4\,\frac{m}{s^2}

b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:

y=m\,x+b\\V(t)=4\,t\,+3

c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:

V(t)= 4\,t+3\\V(1)=4\,(1)+3\\V(1)=7 \,\frac{m}{s}

d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):

Displacement = \frac{(7+15)\,2}{2} = 22\,\,m

e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:

Average velocity = \frac{22}{2} = 11\, \,\frac{m}{s}

3 0
3 years ago
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Hydrogen, hope I helped.
6 0
3 years ago
Three small balls of the same size but different masses are hung side-by-side in parallel on the strings of same length. They to
andrey2020 [161]

Answer:

m1/6 ( c )

Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

After first collision

m1v = m1v1 + m2v2 --- ( 1 )

After second collision

m2v2 = m2v2 + m3v3   ---- ( 2 )

combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3  ----- ( 3 )

All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3

note ; 3p = m1v ∴ m3 = \frac{m1v}{3v3}  -----  ( 4 )

applying conservation of energy

3v = v1 + v2 + v3 ------- ( 5 )

also 3m1v1 = m1v = v1 = v/3 =

v2 + v3 = 8/3 v ----- ( 6 )

next eliminate V3 for equation 6 by applying conservation of energy and momentum

m1 =  2m2 ------ ( 7 )

now using p1 = p2 = m1v1 = 1/2 m1v1  hence v2 = 2v1  where v1 = 1/3 v

hence ; v2 = 2/3 v ------- ( 8 )

solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴  v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

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3 years ago
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