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Darya [45]
3 years ago
7

A 120V Microwave uses 8A of current. It runs for 15 hours over the course of a month. If electrical energy costs $0.11/KWh, what

does it cost to run the microwave for the month
Physics
1 answer:
Reika [66]3 years ago
7 0

Answer:

Monthly energy cost = $47.52

Explanation:

Given the following data;

Voltage = 120 Volts

Current = 8 Ampere

Time = 15 hours

Energy cost = $0.11/KWh

To find the energy cost for a month;

First of all, we would determine the power rating of the microwave oven.

Power = current * voltage

Power = 8 * 120

Power = 960 Watts

Next, we find the amount of energy consumed;

Energy = power * time

Energy = 960 * 15

Energy = 14400 Watt-hour

To kilowatt per hour, we have;

Energy = 14400/1000 = 14.4 KWh

Now, we determine the monthly energy cost;

Daily energy cost = Energy consumption * cost

Daily energy cost = 14.4 * 0.11

Daily energy cost = $1.584

Therefore, monthly energy cost = 1.584 * 30

Monthly energy cost = $47.52

Or

Monthly energy cost = 14.4 * 0.11 * 30

Monthly energy cost = $47.52

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Acceleration is equal to the initial velocity minus the final velocity, then divided by time.true or false
tatiyna

Almost true but not quite.

That would give you the negative of the actual acceleration.

It should be the other way around:

(final v) minus (initial v), then divide by time.

5 0
3 years ago
If 1 meter = 3.28 feet, what is the height of the Washington Monument in meters?
jasenka [17]
Since you didn't provide how tall the Monument was, I took the liberty to find it and it is 555 feet tall. So to convert to meters we must divide 555 by 3.28 or multiply it by 0.3048 (this is the method I used).
555 x 0.3048 = 169.164 meters
5 0
3 years ago
Read 2 more answers
A space station has a large ring-like component that rotates to simulategravity for the crew. This ring has a massM= 2.1×105kg a
ivann1987 [24]

Answer:

Each thruster has to applied a force of 294.5N in tangential direction

Explanation:

Mass of the ring ,M =2.1×105kg

Mass of the ship ,m = 3.5×104kg

Radius of the ring R = 86.0 m

distance of ship from center of the ring, r =31.0 m

Let force applied by each thruster be F

Time taken to reach  gravity ,t = 3hrs = 3600× 3 =10800sec

The movement of ring make the object kept at the edge feel a force of centrifuge in outward direction.

Centrifugal force = weight of the object on earth

Assume the ring is moving with angular speed ω

Centripetalforce of the object kept at ring

m₁R ω²=m₁g  (m₁=mas of object)

⇒Rω² = g

⇒ω = √g/R

The ring start from 0 angular speed with constant angular acceleration

Let the constant angular acceleration be ∝

∝ = ω  / t

(ω = √g/R)

∝ = \frac{1}{t } \sqrt{\frac{g}{R} } }

Consider Torque on the ring and ship system

T = FR + FR = 2FR

Moment of inertia of ring ship system

I = I(ring)+I(ship)+I(ship)

= MR² + mr² + mr² = MR² + 2mr²

angular acceleration of the ring ship system

∝ = \frac{2FR}{MR^2 + 2mr^2}

Now we have ,

∝ = \frac{1}{t} \sqrt{\frac{g}{R} }  , ∝ = \frac{2FR}{MR^2+2mr^2}

equating both values

We have,

F = \frac{MR^2+2mr^2}{2Rt} \sqrt{\frac{g}{R} }

where,

m = 2.1 × 10⁵kg, R = 86m, m = 3.5 × 10₄kg,

r = 31m, g = 9.8m/s² , t = 10800sec

F = \frac{(2.1 \times 10^5 \times86^2)+(2\times3.5v10^4\times31^2) }{2\times86\times10800} \times\sqrt{\frac{9.8}{86} } \\\\F = 294.47N\\\approx294.5N

Each thruster has to applied a force of 294.5N in tangential direction

3 0
3 years ago
What is anything that has mass and volume?
Reika [66]
Matter, substance. Material howya call it.
3 0
3 years ago
If an object has 180 J of PE and a mass of .5kg, what is its height?
Nonamiya [84]
PE=mgh
180=0.5*10*h
180=5h
h=180/5=36 m
7 0
3 years ago
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