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Tomtit [17]
3 years ago
13

Energy can never be created or destroyed just blank or blank

Physics
2 answers:
Liono4ka [1.6K]3 years ago
6 0
The law of conservation of energy states that energy can never be created nor destroyed but it can be conserved or transferred
Sladkaya [172]3 years ago
4 0
Transformes from one form to another like from KE to PE but it doesn't doe
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Llus
ivann1987 [24]

Answer:

kwkwskdkmfmfmdkakksjddndkkakamsjjfjdmakisnddnianbfdnnskake

now

8 0
3 years ago
Read 2 more answers
Looking at group 2 on the periodic table which of these elements probably has the lowest ionic radius
lakkis [162]
I think the answer is Helium.

Please tell me if I'm wrong.
7 0
3 years ago
The cylindrical tub of a dryer in a laundromat rotates counterclockwise about a horizontal axis at 41.5 rev/min as it dries the
frozen [14]

Answer:

\theta = 49.81^0

Explanation:

Given that:

\omega = 41.5 \ rev/min\\\\\omega = 41.5 *\frac{1}{60}* 2 \pi\\\\\omega = 4.45 \ rad/s\\\\\\diameter = 0.748 m

If we let the piece of the close lose contact at ∠θ;

Then ; from force balance;

we have:

\\\\mg sin \theta = \frac{mv^2}{r}\\\\sin \theta = \frac{2v^2}{dg}\\\\\theta = sin^{-1} (\frac{2v^2}{dg})

where;

v = \frac{\omega d}{2}\\\\v =  \frac{4.45 *0.748}{2}\\\\v = 1.6643\\\\v^2 = 2.77

Again:

\theta = sin^{-1}(\frac{2v^2}{dg})\\\\\theta = sin^{-1}( \frac{2*2.77}{0.74*9.8})\\\\\theta = 49.81^0

6 0
3 years ago
A technical machinist is asked to build a cubical steel tank that will hold 130l of water. calculate in meters the smallest poss
disa [49]
Answer:0.507m

To answer this question, you need to know how to calculate a cube volume. Cube volume is calculated by multiplying the length^3, make its unit become cubic meter.
In this case we know the volume is 130L and asked how long is the length in meter. Then you need to convert the liter into m3. The calculation would be:
V=R^3
130L= R^3
R= 3<span>√(130m3/1000)
R= 5.065797/10 m
R= 0.506579m
Rounded up to 0.507m</span>
3 0
3 years ago
Read 2 more answers
A speed skater is sliding across the ice at a speed of 19 m/s when she encounters a rough patch of ice that is 2.0 m wide. As sh
Stells [14]

Answer:

-9.25 m/s^2

Explanation:

The motion of the skater is a uniformly accelerated motion, so we can find the deceleration by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem, we have:

u = 19 m/s is the initial velocity of the skater

v = 18 m/s is the final velocity of the skater

s = 2.0 m is the displacement

Solving for a, we can find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{18^2-19^2}{2(2.0)}=-9.25 m/s^2

And the negative sign tells us that the acceleration is in the opposite direction to the motion (so, it is a deceleration)

5 0
4 years ago
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