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maw [93]
2 years ago
11

If a 50 kg student is standing on the edge of a cliff. Find the student’s gravitational potential energy if the cliff is 40 m hi

gh.
Physics
2 answers:
saul85 [17]2 years ago
8 0
The gravitational potential energy:
E p = m x g x h
where m is the mass and h is the height;
m = 50 kg,  g = 9.81 m/s² ,  h = 40 m
E p = 50 kg  x 9.81 m/s²  x  40 m
Answer:
E p = 19,620 J = 19.62 kJ
timama [110]2 years ago
4 0
E P = 19,620 J = 19.62 kJ
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A pitcher throws a 150g baseball so that it crosses home plate with a speed of 40 m/s. The ball hit straight back towards the pi
Fed [463]

Momentum = (mass) x (velocity)

On the way to the plate, the momentum of the ball was

(0.15 kg) x (40 m/s this way <==) = 6 kg-m/s this way <==

After the hit, the momentum of the ball was

(0.15 kg) x (45 m/s that way ==>) = 6.75 kg-m/s that way ==>

The CHANGE in momentum was 12.75 kg-m/s that way ==>

That's the momentum that the bat gave it.

Change in momentum = Impulse

Impulse = (force) x (length of time the force lasts)

12.75 kg-m/s = (force) x (0.002 second)

Force = (12.75 kg-m/s) / (0.002 second)

<em>Force = 6,375 Newtons, that way ==></em>

4 0
3 years ago
As altitude increases, what happens to air pressure?
Mashcka [7]

Answer:

It decreases

Explanation:

The air pressure tends to be higher on the places with the lowest altitudes, and lower at the places with higher altitudes. Basically, the air pressure is the wight of the air, and since the air is denser and heavier at the lower altitudes, the air pressure is higher, while on the higher altitudes the air is less dense, thus the air pressure is lower. So in practice we can expect that the air pressure in a low valley will be higher than the air pressure at the top of higher mountain.

3 0
3 years ago
Read 2 more answers
For a cylinder of hydrogen (H2) gas, you have been informed that the rms speed of the molecules is 505 m/s. Determine the temper
Svet_ta [14]

Answer:

20.6 K

Explanation:

The root mean square velocity is the square root of the average of the square of the velocity. It can be calculated using the following expression.

v_{rms}=\sqrt{\frac{3RT}{M} }

where,

v_{rms}: root mean square velocity

R: ideal gas constant

T: absolute temperature

M: molar mass

Then, we can find the temperature,

v_{rms}=\sqrt{\frac{3RT}{M} }\\T=\frac{v_{rms}^{2}M }{3R} =\frac{(505m/s)^{2}2.0159 \times 10^{-3} kg/mol}{3 \times (8.314 J/mol.K)} =20.6 K

6 0
3 years ago
Why are graphs useful when interpreting data
aivan3 [116]

Answer:

They make trends in the data easier to see.

5 0
3 years ago
A laser beam of wavelength 600 nm is incident on two slits that are separated by 0.02 mm. What is the separation between adjacen
Liula [17]

Answer:

option D

Explanation:

given,

wavelength = 600 nm

width of separation = 0.02 mm

L = 5 m

for mth order maxima

d \times \dfrac{y_m}{L}=m\lambda

for (m+1)th order maxima

d \times \dfrac{y_{m+1}}{L}=(m+1)\lambda

now,

y_m=\dfrac{mL\lambda}{d}      and

y_{m+1}=\dfrac{(m+1)L\lambda}{d}

hence,

\Delta y = y_{m+1} - y_m

\Delta y =\dfrac{L\lambda}{d}

\Delta y =\dfrac{5 \times 600 \times 10^{-9}}{0.02 \times 10^{-3}}

\Delta y =0.15\ m

\Delta y =15\ cm

hence, the correct answer is option D

4 0
3 years ago
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