Ask question

Ask question

All categories

2 years ago

9

Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. It has a centripetal force. F acting on it. If bod

y 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v, what is the centripetal force acting on it

1 answer:

cluponka [151]2 years ago

8 0

Answer:

The centripetal force on body 2 is 8 times of the centripetal force in body 1.

Explanation:

Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. The centripetal force acting on it is given by :

$F=\dfrac{mv^2}{r}$

Body 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v. The centripetal force on body 2 is :

$F'=\dfrac{2m\times (4v)^2}{4r}\\\\F'=\dfrac{2m\times 16v^2}{4r}\\\\F'=8\dfrac{mv^2}{r}\\\\F'=8F$

So, the centripetal force on body 2 is 8 times of the centripetal force in body 1.

You might be interested in

Below is an "oracle" function. An oracle function is a function presented interactively. When you type in a t value, and press t

Bingel [31]

Answer:

The rate of change of height with respect to time is -10.64 feet/sec

Explanation:

Given that,

There are three lines, so you can calculate three different values of the function at one time.

The function f(t) represents the height in feet of a ball thrown into the air, t seconds after it has been thrown.

Given table is,

Time t = 0, 1, 1,02

Function is, $F(t)=-3.053113177191196\times10^{-18},6.000000000000134, 6.41760000000015$

We need to calculate the initial height of ball

Using equation of motion

$h=h_{0}+ut-\dfrac{1}{2}gt^2$

Where, h₀ = initial height

u = initial velocity

t = time

g = acceleration due to gravity

At t = 0,

Put the value into the formula

$-3.053113177191196\times10^{-18}=h_{0}+0-0$

$h_{0}=-3.053113177191196\times10^{-18}$

We need to calculate the height of ball at t = 1

Using equation of motion

$h_{1}=h_{0}+u_{0}t-\dfrac{1}{2}gt^2$

Put the value in the equation

$6.000000000000134=-3.053113177191196\times10^{-18}+u-\dfrac{1}{2}\times32$

$6.000000000000134+3.053113177191196\times10^{-18}+16=u_{0}$

$u_{0}=22\ feet/s$

Velocity is the rate of change of height with respect to time

So, velocity at 1.02 sec is given

We need to calculate the height

Using equation of motion

$h=ut-\dfrac{1}{2}gt^2$

On differentiating w.r.to t

$h'(t)=u-\dfrac{1}{2}g(2t)$

Put the value into the formula

$h'(t)=22-\times32\times(1.02)$

$h'(t)=-10.64\ feet/sec$

Hence, The rate of change of height with respect to time is -10.64 feet/sec.

4 0

2 years ago

Helga [31]

Answer:

1.129×10⁻⁵ N

1.295 m

Explanation:

Take right to be positive. Sum of forces on the 31.8 kg mass:

∑F = GM₁m / r₁² − GM₂m / r₂²

∑F = G (M₁ − M₂) m / r²

∑F = (6.672×10⁻¹¹ N kg²/m²) (516 kg − 207 kg) (31.8 kg) / (0.482 m / 2)²

∑F = 1.129×10⁻⁵ N

Repeating the same steps, but this time ∑F = 0 and we're solving for r.

∑F = GM₁m / r₁² − GM₂m / r₂²

0 = GM₁m / r₁² − GM₂m / r₂²

GM₁m / r₁² = GM₂m / r₂²

M₁ / r₁² = M₂ / r₂²

516 / r² = 207 / (0.482 − r)²

516 (0.482 − r)² = 207 r²

516 (0.232 − 0.964 r + r²) = 207 r²

119.9 − 497.4 r + 516 r² = 207 r²

119.9 − 497.4 r + 309 r² = 0

r = 0.295 or 1.315

r can't be greater than 0.482, so r = 0.295 m.

5 0

3 years ago

A capacitor is to be constructed to have a capacitance of 100uF.The area of the plates is 6.om by 0.030m and the relative permit

lara [203]

Answer:

The answer is below

Explanation:

Given that:

The area of the plates is 6 m by 0.030 m, Therefore the area = 6 m × 0.03 m = 0.18 m²

the relative permittivity of dielectric (εr) is 7.0

Permittivity of free space (εo) = 8.854 × 10^(-12)

capacitance of 100uF

potential difference (V) of 12V

d = separation between plate

The capacitance (C) of a capacitor is given by:

$C=\frac{\epsilon_o \epsilon_r A }{d}\\ 100*10^{-6}=\frac{8.854*10^{-12}*7*0.18}{d}\\ d=\frac{8.854*10^{-12}*7*0.18}{100*10^{-6}}=1.11*10^{-7}\ m$

The electric field between plates is given as:

E = V /d

$E = 12 / 1.11*10^{-7}=10.75*10^7\ V/m$

3 0

3 years ago

For a projectile launched horizontally, which of the following best describes the downward component of a projectile's velocity?

Angelina_Jolie [31]

C. The downward component of the projectile's velocity continually increases

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion (with constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (equal to the acceleration of gravity) in the downward direction

Here we want to study the downward component of the projectile's velocity. Since the vertical motion is a uniformly accelerated motion, the vertical velocity is given by:

$v=u+at$

where

u = 0 is the initial vertical velocity (zero since the projectile is fired horizontally)

$a=g=9.8 m/s^2$ downward is the acceleration of gravity

t is the time

So the equation becomes

$v=gt$

This means that

C. The downward component of the projectile's velocity continually increases

Because every second, it increases by $9.8 m/s$ in the downward direction.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

8 0

3 years ago

The pressure of air pushing down on a house roof is extremely large. Why is the roof not crushed?

Degger [83]

There is still air inside of a house, which is pushing the roof upwards, so the forces are equal and the roof is not crushed.

7 0

3 years ago