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Ilia_Sergeevich [38]
3 years ago
15

Ap sublevel has 3 electrons. How should they be arranged

Chemistry
1 answer:
galina1969 [7]3 years ago
4 0

Answer:

C.)One electron in each p orbital

Explanation:

In a P-sublevel with 3 electrons, they should be arranged with one electron going into each p-orbitals.

This is in accordance with the Hund's rule of maximum multiplicity.

The rule states that "electrons go into degenerate orbitals or sub-levels(p,d and f) singly before paring up".

Since the p-orbital is 3-fold degenerate with a capacity to accommodate a maximum number of 6 electrons, given 3 electrons, they will follow the Hund's rule in order to fill the orbitals.

So one electron will go in each p - orbitals easily.  

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The balanced combustion reaction for C 6 H 6 C6H6 is 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ 12 CO 2 ( g ) + 6 H 2 O ( l ) + 6542 kJ 2C
Lana71 [14]

Explanation:

First, we will calculate the molar mass of C_{6}H_{6} as follows.

Molar mass of C_{6}H_{6} = 6 \times 12 + 6 \times 1

                                   = 78 g/mol

So, when 2 mol of C_{2}H{6} burns, then heat produced = 6542 KJ

Hence, this means that 2 molecules of C_{6}H{6} are equal to 78 \times 2 = 156 g of C_{6}H_{6} burns, heat produced = 6542 KJ

Therefore, heat produced by burning 5.5 g of C_{6}H{6} =                  

       6542 kJ \times \frac{5.5 g}{156 g}

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            = 228970 J           (as 1 kJ = 1000 J)

It if given that for water, m = 5691 g

And, we know that specific heat capacity of water is 4.186 J/g^{o}C .

As,             Q = m \times C \times (T_{f} - T_{i})

          228970 J = 5691 g \times 4.184 J/g^{o}C \times (T_{f} - 21)
^{o}C

                T_{f} - 21^{o}C = 9.616^{o}C

                T_{f} = 30.6^{o}C

Thus, we can conclude that the final temperature of the water is 30.6^{o}C.

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3 years ago
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