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ICE Princess25 [194]
3 years ago
10

Explain why the lightbulb is not lit when the switch is in the position shown.

Physics
1 answer:
juin [17]3 years ago
7 0
Because the switch isn’t connected to the wire, so the electric charges that is going through the wire isn’t reaching both sockets for the lightbulb.
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A car with a mass of 2.0 * 10^3 kg is traveling at 15 m/s. what is the momentum of the car?
Allushta [10]
Hello,


Your answer to this problem is 400/3


Hope this helps!
3 0
3 years ago
What is the net displacement of the particle between 0 seconds and 80 seconds?
Illusion [34]
After a thorough research, there exists the same question that has choices and the link of the graph (http://i37.servimg.com/u/f37/16/73/53/52/graph410.png)

<span>Choices:
A. 160 meters
B. 80 meters
C. 40 meters
D. 20 meters
E. 0 meters
</span>
The correct answer is letter E. 0 meters.
7 0
3 years ago
PLZ HELP GUYS PLZ!!!!! The answer is not motion, particles.
harina [27]

Answer:

Energy

Explanation:

4 0
3 years ago
Suppose Joe, who can type 40 words per minute, takes 2.5 hours to type his report. To speed things up, his friend Mark offers to
Vika [28.1K]

Explanation:

When Joe works alone, the total number  of words he typed can be given by:

Total words = (40 words per minute) x (60 minutes per hour) x (2.5 hours)

Total words = 6000 words

Now, when Joe and Mark work together, let 'y' be the number of hours for which they both work simultaneously:

Total words = Words Typed by Joe + Words Typed by Mark

6000 = {(40 words per minute) x (60 minutes per hours) x (y hours)} + {(20 words per minute) x (60 minutes per hours) x (y hours)}

6000 = 2400y + 1200y = 3600y

y = 1.67 hours = 1 hour and 40 minutes

Thus, working together simultaneously, Joe and Mark will take 1 hour and 40 minutes to complete the report.

5 0
3 years ago
I'm trying to find the potential energy of a planet using formula G M(sun) x m(planet) / r. I have given G - newton's graviation
ludmilkaskok [199]

Answer:

-5.39\times10^{33} J

Explanation:

Potential energy =

-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J

7 0
2 years ago
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