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2 years ago

What are the various types of technologies used for exploring space and understanding space

Physics

1 answer:

fgiga [73]2 years ago

7 0

The answer is flight technology, satelite technology, and exploration technology.

The flight technology include advances in jet propulsion and navigation. Satelite have become more and more powerful and hecne communication with distant objects is increasing in efficiency. The emergence of AI robots in space exploration are reducing risks to humans in these deep ventures.

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If the mass of the moon is ...

bulgar [2K]

C decreased the factor cuz the max is smaller

8 0

2 years ago

Determine the minimum work per unit of heat transfer from the source reservoir that is required to drive a heat pump with therma

Sloan [31]

Answer:

The minimum work per unit heat transfer will be 0.15.

Explanation:

We know the for a heat pump the coefficient of performance ( $C_{HP}$ ) is given by

$C_{HP} = \dfrac{Q_{H}}{W_{in}}$

where, $Q_{H}$ is the magnitude of heat transfer between cyclic device and high-temperature medium at temperature $T_{H}$ and $W_{in}$ is the required input and is given by $W_{in} = Q_{H} - Q_{L}$ , $Q_{L}$ being magnitude of heat transfer between cyclic device and low-temperature $T_{L}$ . Therefore, from above equation we can write,

$&& \dfrac{Q_{H}}{W_{in}} = \dfrac{Q_{H}}{Q_{H} - Q_{L}} = \dfrac{1}{1 - \dfrac{Q_{L}}{Q_{H}}} = \dfrac{1}{1 - \dfrac{T_{L}}{T_{H}}}$

Given, $T_{L} = 460 K$ and $T_{H} = 540 K$ . So, the minimum work per unit heat transfer is given by

$\dfrac{W_{in}}{Q_{H}} = \dfrac{T_{H} - T_{L}}{T_{H}} = \dfrac{540 - 460}{540} = 0.15$

8 0

3 years ago

If the net force on a 75 - N object is 375 N from the left in what direction will the object move

Katen [24]

It would move to the right because the force is being applied from the left.

5 0

2 years ago

Read 2 more answers

I really need help with this to be able to pass this last semester this is about (Circular Motion ) on physics

ankoles [38]

Question 1
To find centripetal acceleration, use the formula : centripetal acceleration = v^2/r
so answer would be (3.71)^2/42.85=0.32 (2d.p.)
Question 2
Force =ma
a= (9.98)^2/31.77=3.1350
Force= 3.1350 * 56.63 = 177.54 (2 d.p.)

4 0

2 years ago

Read 2 more answers

chuck wagon travels with a constant velocity of 0.5 mile/minutes. determine the total distance traveled by Chuck Wagon during 12

n200080 [17]

Given:

Velocity: 0.5 mile/minute

Time: 12 minute

Now we know that speed and velocity have the same magnitude. Hence speed=velocity=0.5 mile/min

Substituting the given values in the above formula we get

Distance = 0.5 x 12= 6 miles

7 0

3 years ago