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pochemuha
3 years ago
6

Asbestos, HPV, chemicals found in tobacco smoke, and exposure to radioactivity and UV radiation are causes of

Physics
1 answer:
Neko [114]3 years ago
8 0
The BT chemicals in the polymers of the UV radiation and asbestos

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Select the true statements: check all that apply check all that apply oxidizing agents can convert co into co2. a reducing agent
andrew11 [14]

Answer:

1.) True

2.) True

3.) False

Explanation:

1.) Oxidizing agents can convert co into co2.

This is true

Carbon monoxide burns in the oxygen to produce carbon dioxide

2.) A reducing agent gets oxidized as it reacts.

This is true

Because it loses electrons and is oxidized in a chemical reaction. 

3.) If something is reduced, it is formally losing electrons.

This is false.

If something is reduced, it is gaining electrons.

7 0
3 years ago
Rosa records the distance that a toy car rolls and the time it takes to cover the distance. What scientific practice is this?
Sergio039 [100]
Rosa is conducting the scientific practice of observation.
3 0
3 years ago
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What is a hypothesis?
Likurg_2 [28]

Answer:

A

Explanation:

a statement that can be tested through the scientific method

4 0
2 years ago
A car is traveling at a speed of 38.0 m/s on an interstate highway where the speed limit is 75.0 mi/h. Is the driver exceeding t
lidiya [134]

Answer:

Yes, the car driver is exceeding the given limit.

Explanation:

<u>Given:</u>

  • Speed of the car, v = 38.0 m/s.
  • Speed limit of the highway, \rm v_o=75.0\ mi/h.

<h2><u>Converting the speed limit from mi/h to m/s:</u></h2>

We know,

1 mi = 1.60934 km.

1 km = 1000 m.

Therefore, 1 mi = 1.60934 × 1000 m = 1609.34 m.

1 hour = 60 minutes.

1 minute = 60 seconds.

Therefore, 1 hour = 60 × 60 seconds = 3600 seconds.

Using these values,

\rm 1\ \dfrac{mi}{h}=\dfrac{1609.34\ m}{3600\ s}=0.447\ m/s.

Therefore,

\rm v_o = 75.0\ mi/h=75.0\times 0.447=33.52\ m/s.

Clearly,

\rm v_o

which means, the car driver is exceeding the given speed limit.

6 0
3 years ago
The mole fraction of oxygen in dry air near sea level is 0.20948. The concentration of
BlackZzzverrR [31]
C,d,or e you can use the process of elimination to decide...
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3 years ago
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