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Sphinxa [80]
3 years ago
9

The air temperature in a 28 in.3 container with a free sliding piston is initially measured at 45 °

Physics
1 answer:
sergiy2304 [10]3 years ago
8 0

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 659.7 x 28 / 504.7

<span>V2 = 36.60 in^3</span>

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Answer:

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Explanation:

graph a isnt constant

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What step does the Rin PRICES stand for? Why is this step important?
posledela

Explanation:

The five-step process for treating a muscle or joint injury such as an ankle sprain is called "P.R.I.C.E." which is short for Protection, Rest, Ice, Compression, and Elevation).

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Car A has twice the mass of Car B; both travel at the same speed. Compared to Car B. Car A has:
krek1111 [17]

Answer:

Car A has twice the energy of car B.

Explanation:

The kinetic energy of an object is given by :

K=\dfrac{1}{2}mv^2

Where

m is the mass

v is the speed of the object

Car A has twice the mass of Car B. Both travel at the same speed i.e.

m_A=2m_B

So,

\dfrac{K_A}{K_B}=\dfrac{(1/2)m_Av^2}{(1/2)m_Bv^2}\\\\=\dfrac{2m_B}{m_B}\\\\\dfrac{K_A}{K_B}=2\\\\K_A=2\times K_B

So, the kinetic energy of car A is twice of the kinetic energy of car B.

4 0
3 years ago
Read 2 more answers
A stationary 500 kg tank fires a 20 kg miegile at 100 m/s. What is the velocity of the tank after the missile is fired? Assume t
dedylja [7]

Answer:

v₁ = 4 [m/s].

Explanation:

This problem can be solved by using the principle of conservation of linear momentum. Where momentum is preserved before and after the missile is fired.

P=m*v

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

(m_{1}*v_{1})=(m_{2}*v_{2})

where:

m₁ = mass of the tank = 500 [kg]

v₁ = velocity of the tank after firing the missile [m/s]

m₂ = mass of the missile = 20 [kg]

v₂ = velocity of the missile after firing = 100 [m/s]

(500*v_{1})=(20*100)\\v_{1}=2000/500\\v_{1}=4[m/s]

8 0
3 years ago
A boy on a bicycle is resting at the top of a hill. Then, he rides his bicycle
Andreas93 [3]

Answer:

Top: PE = max, KE = 0

Middle: PE = half, KE = half

Bottom: PE = 0, KE = max

Explanation:

The potential energy of an object is the energy possessed by the object due to its location; it is given by

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object from the ground

The kinetic energy of an object is the energy possessed by the object due to its motion; it is given by

KE=\frac{1}{2}mv^2

where

v is the speed of the object

Now we analyze the three situations for the boy on the bycicle:

Top of the hill: here h (the height) is maximum, so the potential energy is maximum, while the speed is zero, therefore the kinetic energy is zero.

Middle of the hill: here h (the height) is half of the initial value, therefore the potential energy is also half of the initial potential energy. According to the law of conservation of energy, the total mechanical energy (potential+kinetic) is constant: this means that also the kinetic energy is half of the initial potential energy.

Bottom of the hill: here h is zero, therefore the potential energy is now zero. As a result, all the mechanical energy has been converted into kinetic energy, therefore the kinetic energy is maximum and it is equal to the potential energy of the boy when he was at the top.

8 0
3 years ago
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