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Sphinxa [80]
3 years ago
9

The air temperature in a 28 in.3 container with a free sliding piston is initially measured at 45 °

Physics
1 answer:
sergiy2304 [10]3 years ago
8 0

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 659.7 x 28 / 504.7

<span>V2 = 36.60 in^3</span>

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A boy is standing motionless on a skateboard. He throws a basketball forward. Describe his motion.
weqwewe [10]

Answer:

Random motion

Explanation:

If the boy throws the basketball forward while at a position on the skateboard, the motion of the ball will be a random motion since we are not told if the ball is moving on a straight line when thrown forward.

In this case, the boy will tend to move in the direction of the ball. Since the ball is moving in a random manner, the motion of the boy will also be a random motion.

A random motion is a motion of a body in a zig zag manner. It is also known as Brownian motion e.g motion of a buzzing mosquito, motion of a smoke coming out of a chimney etc.

8 0
3 years ago
Please help me find the answer
anygoal [31]
B-thymine nucleotides is the answer i am sure
8 0
3 years ago
The work w done when lifting an object varies jointly with the object's mass m and the height h that the object is lifted. the w
Galina-37 [17]
Work done can be computed using the formula:

W=Fd

Where:

W = work (J)
F = Force (N)
d = Distance (d)

Looking at the given, you know that you do not have a value for force, so you will have to solve for it. 

F = ma

Where:

F = Force
m = mass
a = acceleration

Because the object is being lifted, the acceleration will rely on gravity. Acceleration due to gravity is a constant 9.8 m/s^2. Let's list our given first:

F = ?
m = 100kg
a = 9.8m/s^2

Put that into our equation and solve:
F=ma
F=(100kg)(9.8m/s^{2})
F=980kg.m/s^{2}

Our force is then 980 N. 

Now that we have force we can solve for Work. The given for work is as follows:
F= 980N
d = 1.4m

Put that into our formula and solve:
W = Fd
W = (980N)(1.4m)
W = 1,372J

The work done is 1,372J.
7 0
3 years ago
Ill mark as brainliest
Nostrana [21]
Density= mass/volume

in this case density= 1.1g
and the volume = 40 cm^3

so
1.1=40/mass
mass=40/1.1

mass=36.4
7 0
3 years ago
A 100 N uniform ladder of length 5.0 m rest against a smooth wall. The magnitude of the force of the wall, P, acting on the top
amid [387]

Answer:

Explanation:

Wall reactions are never constant as the ladder angle decreases from vertical.

I will ASSUME that the MAXIMUM wall reaction is 40 N before slippage occurs.

Let θ be the ladder angle to horizontal

Moments about the ladder foot will sum to zero

40[5sinθ) - 100[(5/2)cosθ = 0

40[5sinθ) = 100[(5/2)cosθ

 200sinθ = 250cosθ

sinθ/cosθ = 250/200

        tanθ = 1.25

             θ = 51.34019174...

            θ = 51°

4 0
2 years ago
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