Answer:
The radius of the gold nucleus is 7.1x10⁻¹⁵m
Explanation:
The nearest distance is:
(eq. 1)
Where
z = atomic number of gold = 79
e = electron charge = 1.6x10⁻¹⁹C
k = electrostatic constant = 9x10⁹Nm²C²
energy of the particle = 32 MeV = 5.12x10⁻¹²J
At the potential energy is zero, all the energy will be kinetic energy:
Where
m = 4 mp = mass of proton
Replacing in equation 1
Answer:
10N each
Explanation:
Doing a little math here to make it balanced. 10+10=20 therefore you have the same on both sides.
Hope this helps!
Answer:
La velocidad media es 5 
, que equivale a 1.389 
Explanation:
La velocidad es una magnitud física que expresa la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello.
La velocidad media relaciona el cambio de la posición con el tiempo empleado en efectuar dicho cambio. Por lo que se calcula como la distancia recorrida por un objeto dividido por el tiempo transcurrido:
En este caso:
- distancia= 10 km= 10,000 m (siendo 1 km= 1,000 m)
- tiempo= 2 h= 7,200 s (siendo 1 h= 3,600 s)
Entonces, reemplazando en la definición de velocidad media:
Resolviendo se obtiene:
<u><em>La velocidad media es 5 </em></u><u><em>, que equivale a 1.389 </em></u><u><em></em></u>
The answer is C because if it’s moving with a constant speed it’s gonna be balanced and there will be no force
Consider the motion towards right as positive and motion towards left as negative.
m₁ = mass of the cart moving to right = 0.500 kg
v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s
m₂ = mass of cart moving to left = 0.800 kg
v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s
initial momentum of the system of carts before the collision is given as
P₁ = m₁ v₁ + m₂ v₂
P₁ = (0.500) (2.2) + (0.800) (- 1.1)
P₁ = 0.22 kg m/s
P₂ = momentum of system of carts after collision
As per conservation of momentum,
Momentum of system of carts after collision = Momentum of system of carts before collision
P₂ = P₁
P₂ = 0.22 kg m/s
