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3 years ago

3x/y=6g/b solve for x

1 answer:

5 0

So looking at the problem, you are going to want to start by finding a common denominator (1) in this case: yb, and combining like terms (2). You are then going to want to multiply both sides by (yb) as the reciprocal to the fractions (3).
1) 3x 6g
---- = ---
y b

2) 3xb 6gy
------ = -----
yb yb

3) 3xb 6gy
(yb) ------ = -----
yb yb
which becomes: 3xb = 6gy

So after this, things become much more simple, as all you have to do is isolate the (x), which can be done by dividing the entire equation by (3b).

3xb 6gy
----- = -----
3b 3b

where you will then find your answer of:
2gy
x = ----- (simplified by the GCM of 3)
b

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4 years ago

I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52

Oduvanchick [21]

Answer:

28.1 m/s

Explanation:

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$y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}$

$v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}$

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction $u_x=v_x=1.52\ \text{m/s}$

Resultant velocity is given by

$v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}$

The fish is moving at a velocity of 28.1 m/s when it hits the water.

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3 years ago

Can someone help me please. i will give you a brainliest. thanks!

steposvetlana [31]

Answer:

sry don't know but can u give me brainlliest

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3 years ago