Answer:
n = 756.25 giga electrons
Explanation:
It is given that,
If the charge on the negative plate of the capacitor, 
Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

e is the charge on electron

or
n = 756.25 giga electrons
So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.
To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

Where,
= Mass of each object
= Initial Velocity of Each object
= Final Velocity
Our values are given as




Replacing we have that



Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s
Given Information:
Mass of sock = 0.23 kg
Stretched length of sock = x = 2.54 cm = 0.0254 m
Required Information:
Spring constant = k = ?
Answer:
Spring constant = k = 88.82 N/m
Explanation:
We know from the Hook's law that
F = kx
Where k is spring constant, F is the applied force and x is length of sock being stretched.
k = F/x
Where F is given by
F = mg
F = 0.23*9.81
F = 2.256 N
So the spring constant is
k = 2.256/0.0254
k = 88.82 N/m
Therefore, the spring constant of the sock is 88.82 N/m