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2 years ago

Co Shawn can jog 5 mile in 5 hour. What is his average speed per hour?

Mathematics

2 answers:

Reptile [31]2 years ago

4 0

Answer:

Hey jude i am sorry but Shawn and i need to go get ready because he is about to release another song from his new album.!!!!!

Step-by-step explanation:

Blizzard [7]2 years ago

4 0

Answer:

One mile per hour.

Step-by-step explanation:

If Shawn can jog 5 miles in 5 hours, to find his average speed (in miles) per hour, we can divide 5 miles into 5 hours:

$\frac{5}{5}$

$=\frac{1}{1}$

Therefore, Shawn's average speed per hour is one mile per hour.

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Data from the Centers for Medicare and Medicaid Services indicates that the annual per capita out-of-pocket expenses for health

Talja [164]

Answer:

During the year 2021.

Step-by-step explanation:

As we have a function that defines the annual per capita out-of-pocket expenses for health care, we can work with it.

Knowing that, we clear x (this is the number of years past the year 2000, so it will contain our desired information).

$y=39.6x+543\Leftrightarrow x=\frac{y-543}{39.6}$

Now, as we want to know when are the per capita out-of-pocket expenses for health care predicted to be $1400, and this total is our variable y, then

$x=\frac{1400-543}{39.6}\approx 21.6$

Finally, we know that x is the number of years past the year 2000, so the answer is that during the year 2021, the per capita out-of-pocket expenses for health care are predicted to be $1400.

3 0

2 years ago

Thomas bought a case of 6 apple juice bottles and one 3-liter bottle of orange juice. Each apple juice bottle contains 2 liters

OleMash [197]

So...
Each bottle of apple juice has 2 litters of juice, so, if he bought y bottles of apple juice, we will have to multiply.
$6*2=12$

12 liters of apple juice
3 liters of orange juice

6 0

2 years ago

Last month you spent $30 on clothing. This month you spent 150% of what you spent last month. Set up a proportion to model thi

valentinak56 [21]

Answer:

$45

Step-by-step explanation:

x=1.5(30)

x=45

6 0

2 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

2 years ago

The average human heart beats 1.15 \cdot 10^51.15⋅10 5 1, point, 15, dot, 10, start superscript, 5, end superscript times per da

andriy [413]

Answer:

$4.1975\cdot 10^{7}$

Step-by-step explanation:

We are told that the average human heart beats $1.15\cdot 10^{5}$ times per day and there are $3.65\cdot 10^{2}$ days in one year.

To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.

$1.15\cdot 10^{5}\times 3.65\cdot 10^{2}$

Now we will solve this problem using exponent properties.

$1.15 \times 3.65\cdot 10^{2+5}$

$1.15 \times 3.65\cdot 10^{7}$

$4.1975\cdot 10^{7}$

Our answer is in scientific notation we can represent it in standard form as $4.1975\cdot 10^{7}=4.1975*10000000=41975000$ times.

Therefore, average human heart beats in one year $4.1975\cdot 10^{7}$ or 41975000 times.

4 0

2 years ago

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