Question

A 1 mol sample of gas has a temperature of 225K, a volume of 3.3L, and a pressure of 500 torr. What would the temperature be if the amount of gas remains constant while pressure dropped to 210 torr, and the volume dropped to 2.75L?

Answer 1

Answer:

78.75 K

Explanation:

We are given;

• Initial pressure, P₁ = 500 torr
• Initial temperature,T₁ = 225 K
• Initial volume, V₁ = 3.3 L
• Final volume, V₂ = 2.75 L
• Final pressure, P₂ = 210 torr                        

We are required to calculate the new temperature, T₂

• To find the new temperature, T₂ we are going to use the combined gas law;
• According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

We can calculate the new temperature, T₂;

Rearranging the formula;

T₂ =(P₂V₂T₁) ÷ (P₁V₁)

  = (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)

  = 78.75 K

Therefore, the new volume of the sample is 78.75 K