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ludmilkaskok [199]
3 years ago
15

An American Red Cross plane needs to drop emergency supplies to victims of a hurricane in a remote part of the world. The plane

is traveling horizontally at 100.0 m/s at a height of 50.0 m above the ground. What horizontal distance does the package travel before striking the ground?

Physics
1 answer:
Andreas93 [3]3 years ago
3 0
Refer to the diagram shown below.

Assume that air resistance is ignored.

Note:
The distance, h, of a falling object with initial vertical velocity of zero at time t is
h = (1/2)gt²
where
g = 9.8 m/s²

The initial vertical velocity of the supplies is 0 m/s.
It the time taken for the supplies to reach the ground is t, then
(50 m) = (1/2)*(9.8 m/s²)*(t s)²

Hence obtain
t² = 50/4.9 = 10.2041
t = 3.1944 s

The horizontal distance traveled at a speed of 100 m/s is
d = (100 m/s)*(3.1944 s) = 319.44 m

Answer: 319.4 m (nearest tenth)

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A certain superconducting magnet in the form of a solenoid of length 0.26 m can generate a magnetic field of 7.5 T in its core w
Mars2501 [29]

Answer:

Therefore

Number of turns in the solenoid is 19407.

Explanation:

Given:

Strength magnetic field at its center,

B = 7.5 T

length of solenoid = l = 0.26 m

Current, I = 80 A

To Find:

Turn = N = ?

Solution:

If N is the number of turns in the length, the total current through the rectangle is NI. Therefore, Ampere’s law applied to this path gives

\int {B} \, ds= Bl=\mu_{0}NI

Therefore,

B =\dfrac{\mu_{0}NI}{l}

Where,  

B = Strength of magnetic field

l = Length of solenoid

N = Number of turns

I = Current

\mu_{0}=Permeability\ in\ free\ space=4\pi\times 10^{-7}\ Tm/A

N=\dfrac{Bl}{\mu_{0}I}

Substituting the values we get

N=\dfrac{7.5\times 0.26}{4\pi\times 10^{-7}\times 80}=19406.84=19407

Therefore

Number of turns in the solenoid is 19407.

8 0
3 years ago
The brain is most active during which portion each sleep cycle
s2008m [1.1K]
Its during REM sleep. hope this helped
7 0
3 years ago
Read 2 more answers
___________ force can be thought of as either a push or a pull, as long as it makes the object move in a circular path.
fomenos
I believe it would be the Centripetal force.
5 0
3 years ago
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A 60 g ball of clay is thrown horizontally at 40 m/s toward a 1.5 kg block sitting at rest on a frictionless surface. the clay h
Bingel [31]
The solution for this problem is:
Let u denote speed. 

Equating momentum before and after collision: 
= 0.060 * 40 = (1.5 + 0.060) u 
= 2.4 = 1.56 u
= 2.4 / 1.56 = 1.56 u / 1.56
= 1.6 m / s is the answer for this question. This is the speed after the collision.
7 0
3 years ago
The drag on a pitched baseball can be surprisingly large. Suppose a 145 g baseball with a diameter of 7.4 cm has an initial spee
kupik [55]

Answer:

<h2>Part A)</h2><h2>Acceleration of the ball is 10.1 m/s/s</h2><h2>Part B)</h2><h2>the final speed of the ball is given as</h2><h2>v_f = 35.3 m/s</h2>

Explanation:

Part a)

As we know that drag force is given as

F = \frac{C_d \rho A v^2}{2}

C_d = 0.35

A = \frac{\pi d^2}{4}

A = \frac{\pi(0.074)^2}{4}

A = 4.3 \times 10^{-3} m^2

v = 40.2 m/s

so we have

F = \frac{0.35\times 1.2 (4.3 \times 10^{-3})(40.2)^2}{2}

F = 1.46 N

So acceleration of the ball is

a = \frac{F}{m}

a = \frac{1.46}{0.145}

a = 10.1 m/s^2

Part B)

As per kinematics we know that

v_f^2 - v_i^2 = 2 a d

v_f^2 - 40.2^2 = 2(-10.1)(18.4)

v_f = 35.3 m/s

4 0
3 years ago
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