Work= F times d so force x distance
25(.5) is 12.5
<span>closing the switch completes the circuit</span>
<span>So we wan't to know what will the Coulomb force be between two charged baloons will be if we double the distance between the them and Fc=0.16N. The coulomb force between two charges is Fc=k*Q1*Q2/r^2. So we see from the equation that the magnitude of the force will be smaller as we increase the distance. So let's increase the distance from r to R=2r. If we input thai into the equation we get: Fc=k*Q1*Q2/R^2. Now: Fc=k*Q1*Q2/(2r)^2. And finally: Fc= k*Q1*Q2/4r^2. And if we factor out 1/4 we get: Fc=(1/4)*k*Q1*Q2/r^2. Now we can see that if we double the distance the magnitude of the force will be smaller for a factor of 1/4 or the magnitude of the force will be smaller 4 times. So finally the force is (1/4)*0.16N= 0.04N. So the correct answer is A. 0.04 newtons. </span>
Answer:
Wien peak ( λmax ) is 107.40 nm
radius of super giant is 1.086 ×
m
Explanation:
given data
temperature 27 kK
power = 100000 times of Sun
Sun radius = 6.96 × 10^8 m
to find out
Wien peak ( λmax ) and radius of supergiant (r)
solution
we will apply here first wien law to find Wien peak that is
λmax = b / t
λmax = 2.9 × 
/ 27000 = 1.0740 × 
so Wien peak ( λmax ) is 107.40 nm
and
now we apply steafay law that is
P = σ × A × 
.........................1
and we know total power output 100000 time of Sun
so we say
4πr²s = 100000 × 4πR²s
r² = 100000 × R² /
put here value
r² = 100000 × (6.96×
)² × 
/ 
r² = 1.18132 ×
r = 1.086 × m
so radius of super giant is 1.086 × m
Assuming that’s a right triangle, in this case A^2 + C^2 = B^2 … (16)^2 + C^2 = (25)^2 … C = 19.2 N
