If we compare a cell with an egg there is a major difference between the outer membrane
in case of cell they are bounded by semi permeable membrane
The semi permeable membrane is a selectively permeable membrane which allows the movement of only solvent molecule and not solute molecules through it.
So water can move into or out of the cell through cell membrane by a special physical process known as osmosis.
the water will move from a low concentration gradient to high concentration gradient.
Answer: 2HCO + 4O → H2 + 2CO3
Explanation: Oxomethyl + Oxygen = Dihydrogen + Carbon Trioxide
Reaction Type: SINGLE REPLACEMENT
***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***
I read and said it's a weak base
Answer:
in both nucleophil attach the c and leaving group leave but in acyl nu. subsituation c of carbonyl because of double bond with o have bigger positive charge and is better electrophil so do it faster,also alkyl nu. subsituation can have rearangment if going from sn1 and in sn2 sterichemistry of molecule change , acyl nu. subsituation most of time is better
<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>
What is benzoic acid found in?
- Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
- Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.
Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.
Amount of moles of NaOH -2 × 0.025 = 0.05 mol
Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol
In this case, we can calculate the pH produced by the buffer of these two reagents, as follows


We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows




Now we must solve the equation above. This will be done using the following values

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.
NaOH volume
( 0.5 - 0.464)L
0.036L .................... 36ml
HCOOH volume
500 - 36 = 464mL
Learn more about benzoic acid
brainly.com/question/24052816
#SPJ4