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liberstina [14]
3 years ago
10

Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 2.6 m long, its mass is 0.5

kg, and the force exerted by the children is 44 N. What is the speed of the waves on the rope
Physics
1 answer:
Irina-Kira [14]3 years ago
6 0

Answer:

15.13 m/s

Explanation:

The wave speed of the stretched rope can be calculated using the following formula

v = \sqrt{\frac{F_T}{\mu}}

where F_T = 44N is the tension on the rope and \mu = m/L = 0.5 / 2.6 = 0.1923 kg/m is the density of the rope per unit length

v = \sqrt{\frac{44}{0.1923}} = \sqrt{228.8} = 15.13 m/s

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This is for physics, i need help fast!!
jarptica [38.1K]
Speed = distance / time
S= 40 000m / 5400s
S= 7.41m/s
7 0
3 years ago
A tub of water is placed in a small room and heat is removed from the room. What will most likely occur if enough heat is remove
NARA [144]

Answer:

(A)The water will freeze.

Explanation:

Heat is the energy that when transferred causes change in temperature. If heat is added to a body by some process the bodies temperature increases and if heat is removed from a body by some process the temperature reduces.

In this case if enough heat is removed from the room the internal movement of the water particles will slow down causing the water to form crystal lattice thus forming ice. So, the water will freeze.

6 0
3 years ago
Read 2 more answers
Which of the following physical properties would tell you about an element's mass per unit volume ratio?
Igoryamba
Well I can't see the following physical properties you talked about in the question.

Mass per unit volume ratio is called density.
6 0
3 years ago
A nonuniform, but spherically symmetric, distribution of charge has a charge density ρ(r) given as follows: ρ(r)=ρ0(1−r/r) for r
Nadusha1986 [10]

A)<span>
dQ = ρ(r) * A * dr = ρ0(1 - r/R) (4πr²)dr = 4π * ρ0(r² - r³/R) dr 
which when integrated from 0 to r is 
total charge = 4π * ρ0 (r³/3 + r^4/(4R)) 
and when r = R our total charge is 
total charge = 4π*ρ0(R³/3 + R³/4) = 4π*ρ0*R³/12 = π*ρ0*R³ / 3 
and after substituting ρ0 = 3Q / πR³ we have 
total charge = Q ◄ 

B) E = kQ/d² 
since the distribution is symmetric spherically 

C) dE = k*dq/r² = k*4π*ρ0(r² - r³/R)dr / r² = k*4π*ρ0(1 - r/R)dr 
so 
E(r) = k*4π*ρ0*(r - r²/(2R)) from zero to r is 
and after substituting for ρ0 is 
E(r) = k*4π*3Q(r - r²/(2R)) / πR³ = 12kQ(r/R³ - r²/(2R^4)) 
which could be expressed other ways. 

D) dE/dr = 0 = 12kQ(1/R³ - r/R^4) means that 
r = R for a min/max (and we know it's a max since r = 0 is a min). 

<span>E) E = 12kQ(R/R³ - R²/(2R^4)) = 12kQ / 2R² = 6kQ / R² </span></span>

4 0
3 years ago
Describe the relationship between the pressure and volume of a gas when temperature and mass are constant
mr_godi [17]

Answer:

The product of Pressure and Volume is a constant.

Explanation:

We know the Ideal gas equation,

PV  =  nRT,

where,

P -  Pressure of the gas

V -  Volume of the gas

n -  No. of moles of the gas taken

R -  Universal Gas Constant.

T - Temperature of the gas.

We know that ,  n  =  \frac{wt}{Mwt}

where, wt - Mass of gass ; Mwt - Molecular weight of the gas.

We are given the weight of the gas remains constant (wt is a constant)

Therefore as n = \frac{wt}{Mwt},(where both wt and Mwt are constants)

n is a constant in this process.

Universal gas constant is a constant

Given temperature is a constant.

Therefore,

As, PV = nRT,  (where n,R,T are constants),

PV is a constant.

Therefore we can say,

PV = k,  for some constant k.

If we plot a graph for P vs V , we get a Rectangular Hyperbola( One of the general forms of a Rectangular Hyperbola is xy = c)

5 0
4 years ago
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